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3 years ago

Why am i not good enough for my mom

2 answers:

8 0

You are good enough in general. As long as you know and feel that you are good enough within yourself, you won’t have to worry about meeting anyone else’s expectations. Maybe it’s your mom.. not you.

Zolol [24]3 years ago

7 0

Answer:

please don't feel like you're not good enough because you are. Trust me. you are more than enough, do not listen to your mom if she is being mean.

Explanation:

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Which of the following could be true of two species that have a competitve ralationship in the same ecosystems Help me out pleas

ankoles [38]

The answer is b. as a whole, the species is mutually beneficial to carry on each others traits and exist in the same ecosystem.

6 0

3 years ago

Read 2 more answers

A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35?C. If there are 9750 moles of oxygen in the tan

Paul [167]

Answer:

2192.64 PSI.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.

To convert from atm to PSI:

1 atm = 14.696 PSI.

∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.

4 0

2 years ago

A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix

Alisiya [41]

Answer:

$M_f=38.8\%$

Explanation:

From the question we are told that:

Pressure $P=747mmHg$

Temperature $T=298K$

Volume $V=11.1$

Heat Produced $Q=780kJ$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

$n= (747/760) *11.1/ (0.0821*298)$

$n=0.446mol$

Therefore

$x+y=0.446$

$x=0.446-y .....1$

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

$x(889) + y(2220) = 760 ...... 2$

Comparing Equation 1 and 2 and solving simultaneously

$x=0.446-y .....1$

$x(889) + y(2220) = 760 ...... 2$

$x=0.173$

$y=0.273$

Therefore

Mole fraction 0f Methane is mathematically given as

$M_f=\frac{x}{n}*100\%$

$M_f=\frac{1.173}{0.446}*100\%$

$M_f=38.8\%$

7 0

2 years ago

One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet

PSYCHO15rus [73]

Answer:

$2.4*10^{7}cm^{3}$

Explanation:

First you should calculate the volume of a big sphere,so:

$V_{big}=\frac{4}{3}\pi r^{3}$

$V_{big}=\frac{4}{3}\pi (181cm)^{3}$

$V_{big}=2.4*10^{7}cm^{3}$

Then you calculate the volume of a small spehre, so:

$V_{small}=\frac{4}{3}\pi r^{3}$

$V_{small}=\frac{4}{3}\pi (5.01cm)^{3}$

$V_{small}=5.3*10^{2}cm^{3}$

Finally you subtract the two quantities:

$V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}$

$V_{big}-V_{small}=2.4*10^{7}cm^{3}$

5 0

2 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, n, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.

$w_\text{max} = n \cdot F \cdot E_\text{cell}$ , where

n is the number of moles electrons transferred,
F is the Faraday's constant,
E $_\text{cell}$ is the cell potential,

n = 0.144 mol, as shown above, and

F = 96.486 kJ / ( $\text{V} \cdot \text{mol} \; \text{e}^{-}$ ).

Therefore,

$w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}$ .

3 0

3 years ago