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Lelu [443]
3 years ago
7

You make tea with 0.50 kg of 85.0°C water and let it cool to room temperature 120.0°C2.

Physics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

Explanation:

a ) Entropy change dS = dQ/T

= mcdT /T

Integrating both sides

S₂ - S₁ = - mclnT₂ /T₁

= - .5 X 4200 ln (85+273) /( 20 + 273 )

.5 X 4200 ln 358/ 293

= - 417.6 J/K

Entropy change will be negative as heat is lost by the system .

b ) Sine there is no change in the temperature of air , This heat will enter air at temperature ( 20+ 273) K = 293 K

Heat entering air

= .5 x 4200 x 65

= 136500 J

Change in entropy

136500 / 293 ( room temperature is constant at 293k

= + 465.87 J/K

Entropy change will be positive  as heat is gained  by the system .

Total change in the entropy of the system (tea + air )

= +465.87 - 417.6

= 48.27 J/K

Entropy change will be negative as heat is lost by the system .

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Answer:

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Explanation:

According to ohm's law V = IR where;

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In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.

For line B, R = ΔV/ΔI

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R = 14.0-4.0/7.0-2.0

R = 10.0/5.0

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Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.

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3 years ago
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Answer:

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OPTION A

Explanation:

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Given

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frequency =  \frac{speed}{wavelength} =  \frac{345}{4.15}

frequency = 83 \: hertz

I hope it helped you

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