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2 years ago

14

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the

two balls collide, the final momentum of the cue ball is 0.01 kg m/s

1 answer:

ella [17]2 years ago

5 0

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

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Mrs. Paul and Dr. Mykannen ride a tandem bike on the beach. They ride along the beach for about 455 meters. Their final velocity

algol [13]

Answer:

Time = 80.91 seconds

Explanation:

Given the following data;

Velocity = 5.50 m/s.

Distance = 445 meters

To find the time;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

$Velocity = \frac{distance}{time}$

Substituting into the formula, we have;

5.5 = 445/time

Time = 445/5.5

Time = 80.91 seconds

5 0

2 years ago

A satellite’s velocity is 30000m/s. After 60 secs, it’s velocity shows to 15000m/a. What is the satellite’s acceleration?

Orlov [11]

Answer:

Acceleration = 9 × 10^5 m/s^2 ( deceleration )

Explanation:

From the first equation of motion:

V = u + at

15000 = 30000 + 60a

a = ( 15000-30000)/60

a = 9 × 10^5 m/s^2

4 0

3 years ago

Two cars collide inelastically and stick together after the collision. Before the collision, the magnitudes of their momenta are

dolphi86 [110]

Answer:

a) P1+P2

Explanation:

The magnitude of their combined momentum is just the addition of each momentum, because in this case of inelastic collision, the kinetic energy of the two cars are both converted to some form of energy because the velocity of both cars becomes zero, i.e., V=0, making P = mv = 0, this means the magnitude of P1 + P2 = 0.

3 0

3 years ago

Which of Kepler's laws describes the speed at which planets travel at different points in their orbit around the Sun?

vagabundo [1.1K]

D. This says the path sweeps out equal segments of the elliptical path in equal times (picture a wedge of a pie shaped like an oval)

4 0

3 years ago

Read 2 more answers

A train is approaching a town at a constant speed of 12 m/s. The town is 1.0 km distant. After 30 seconds, the conductor applies

Yuliya22 [10]

To solve this problem we will apply the linear motion kinematic equations. To determine the position in which the braking starts we will start from the definition of distance as a function of speed and time, that is

$x = x_0 - vt$

Here,

$x_0$ = Initial position

v = Velocity

t = time

Replacing we have that

$x = 1000-12*30$

$x = 640m$

Now the acceleration is given by the function,

$v_f^2=v_0^2 +ax$

Here,

$v_f$ = Final velocity

$v_0$ = Initial velocity

a = Acceleration

x = Displacement

Replacing we have that

$0 = 12^2+2a(640)$

$a = -0.1125m/s^2$

Therefore the acceleration necessary to bring the train to rest is $-0.1125m/s^2$

4 0

3 years ago