Ask question

Ask question

All categories

2 years ago

14

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the

two balls collide, the final momentum of the cue ball is 0.01 kg m/s

1 answer:

ella [17]2 years ago

5 0

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

You might be interested in

What is the atomic number of a sodium atom that has 11 protons and 12 neutrons

Ede4ka [16]

The Atomic number for sodium is 11 cause it contains 11 protons. I hope this helps..

8 0

3 years ago

Temperature of the resistor in an RC circuit. In this problem we will look at the temperature response of the resist

fomenos

RC circuit determines the capacitor's charging rate.

In RC (resistive and capacitive) circuits, a capacitor's time constant is the number of seconds required to charge it to 63.2% of the input voltage.

This duration is described by a single time constant. After two time constants, the capacitor will be charged to 86.5% of the input voltage.
The RC time constant, also referred to as tau, is the time constant (in seconds) of an RC circuit and is obtained by multiplying the circuit resistance (in ohms) by the circuit capacitance (in farads), This transient reaction time T is stated in terms of = R x C, where R is the resistor value in ohms and C is the capacitor value in farads.

Learn more about RC circuits here brainly.com/question/13450553

#SPJ4.

4 0

1 year ago

Given that an atom of a semiconductor has a diameter of 2.18 å , what is the maximum number of moles that fit in the channel of

andrezito [222]

<span>Convert angstroms to nm for atom diameter 2.18/10=.218 nm. Divide diameter by length width and height. 63.6/.218=292 74.2/.218=327 275/.218=1261 Multiply these to get volume of atoms 120,037,500 Convert atoms to moles using Avogadro number 120,037,500/6.02*10^23=2*10^-16 moles</span>

7 0

4 years ago

Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30

beks73 [17]

Answer:

T=575.16K

Explanation:

To solve the problem we proceed to use the 1 law of diffusion of flow,

Here,

$J=-D\frac{\Delta C}{\Delta x}$

$\Delta C$ is the rate in concentration

$\Delta x$ is the rate in thickness

D is the diffusion coefficient, where,

$D= D_0 exp(\frac{Q_d}{RT})$

Replacing D in the first law,

$J=-(D_0 exp(\frac{-Q_D}{RT}))\frac{\Delta }{\Delta x}$

clearing T,

$T=\frac{Q_d}{R*ln(\frac{J*\Delta x}{D_0*\Delta C})}$

Replacing our values

$T=-\frac{80000}{8.31*ln(\frac{(6.2*10^{-7})(-15*10^{-3})}{(1.43*10^{-9})(0.65-0.30)})}$

$T=-\frac{80000}{-138.09}$

$T=575.16K$

4 0

3 years ago

What mass of ice (in g) can be melted if 27.2 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol

san4es73 [151]

Answer : The mass of ice melted can be, 3.98 grams.

Explanation :

First we have to calculate the moles of ice.

$Q=\frac{\Delta H}{n}$

where,

Q = energy absorbed = 27.2 kJ

$\Delta H$ = enthalpy of fusion of ice = 6.01 kJ/mol

n = moles = ?

Now put all the given values in the above expression, we get:

$27.2kJ=\frac{6.01kJ/mol}{n}$

$n=0.221mol$

Now we have to calculate the mass of ice.

$\text{Mass of ice}=\text{Moles of ice}\times \text{Molar mass of ice}$

Molar mass of ice = 18.02 g/mol

$\text{Mass of ice}=0.221mol\times 18.02g/mol=3.98g$

Thus, the mass of ice melted can be, 3.98 grams.

3 0

4 years ago