8. What is the rate of change in an object’s position?

2 answers:

4 0

A similar but separate notion is that of velocity, which the rate of change of position. Example . If p(t) is the position of an object moving on a number line at time t (measured in minutes, say), then the average rate of change of p(t) is the average velocity of the object, measured in units per minute.

Sloan [31]3 years ago

4 0

the rate at which an object changes position. but if you need a number or a formula i need to know if its on a hill. what panet. what the object is. etc. etc. etc.

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11. A student lifts a 25 kg mass a vertical distance of 1.6 m in a time of 2.0 seconds.

goldenfox [79]

Answer:

a) 245 N

b) 392 J

c) 196 W

Explanation:

a) Force needed to lift the 25 kg object is the same as the weight of the object:

$Force= m * g = 25kg * 9.8 \frac{m}{s^2} = 245 N$

b) Work is the force exerted times the distance moved:

$Work = F * d = 245N * 1.6 m = 392 Joules = 392 J$

c) The power exerted is the quotient of the work done over the amount of time it took to move the object:

4 0

3 years ago

Compute the ratio of the rate of heat loss through a single-pane window with area 0.15 m2 to that for a double-pane window with

Rudik [331]

Answer:

2.80321285141

Explanation:

$L_g$ = Thickness of glass = 4.5 mm

$k_g$ = Thermal conductivity of glass = 0.8 W/mK

$R_0$ = Combined thermal resistance = $0.15\times m^2K/W$

$L_a$ = Thickness of air = 6.6 mm

$k_a$ = Thermal conductivity of air = 0.024 W/mK

The required ratio is the inverse of total thermal resistance

$\dfrac{2(L_g/k_g)+R_0+(L_a/k_a)}{(L_g/k_g)+R_0}\\ =\dfrac{2(4.5\times 10^{-3}/0.8)+0.15+(6.6\times 10^{-3}/0.024)}{(4.5\times 10^{-3}/0.8)+0.15}\\ =2.80321285141$