To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.
If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,
So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
Well if it was traveling for an hour then the answer is 8 miles.
An object will stay in motion unless acted upon by an UNBALANCED force.
Answer:
0.230 s
Explanation:
The period is the length of time from one peak to the next. If it takes the oscillator 0.115 s to go from the lowest point to the highest point, then it takes another 0.115 s to return to the lowest point. So the period is 0.115 + 0.115 = 0.230 seconds.
That depends on where you weigh it.
-- On Earth, it weighs 9.807 newtons (2.205 pounds).
-- On the moon, it weighs 1.623 newtons (5.84 ounces).
-- On Jupiter, it weighs 24.79 newtons (5.57 pounds).
BTW ... 1,000 grams of mass is called ' one kilogram '.
