1) KE=1/2*m*v^2
1/2*45*40^2
KE=36,000J
2) PE=mgh
45*9.81*30
PE=13243.5J
Answer:
Explanation:
Area of electrodes, A = 2 cm x 2 cm = 4 cm²
Separation between electrodes, d = 1 mm
Voltage, V = 9 V
(a)
Let C is the capacitance between the electrodes
C = 3.54 x 10^-12 F
Let q be the charge on each of the electrode
q = C x V
q = 3.54 x 10^-12 x 9 = 3.2 x 10^-11 C
(b)
As, the battery is disconnected the charge on the electrodes remains same.
(c)
As the battery is connected the voltage is same.
capacitance is change.
As the distance is doubled, the capacitance becomes half and the charge is also halved. q' = q/2 = 1.6 x 10^-11 C
Answer:
Option C, The total momentum of the fragments is equal to the original momentum of the firecracker.
Explanation:
Kinetic energy of cracker cannot remain constant before and after explosion. It is so because in the process of burning and bursting some amount of kinetic energy is lost in the form of light and heat energy. While the total mass before and after the explosion remains constant due to which the momentum is conserved before and after the explosion
Hence, option C is correct
Answer:
navigator Jacques Cartier
Explanation:
<u>Displacement</u> is the difference between final position and initial position.
<u>Momentum</u> is the quantity of motion contained by an object.
- It is the product of <em><u>mass and velocity.</u></em>
