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Marianna [84]
3 years ago
10

PLEASEEE HELPPPP

Physics
2 answers:
Evgen [1.6K]3 years ago
6 0

Answer:

The average car speed is  25.4 m/s

Explanation:

The definition of average speed is the total distance traveled between the total time

     Vm = dx/dt        (1)

To be able to use this equation let's calculate the total carriage distance

     Xt = X1 + X2

     X1 = 10 miles 1609  m / 1 miles = 16090 m

     X2 = 10 miles 1609 m / 1miles = 16090 m

     XT = 32180 m

Now let's calculate the total time

      v = d / t

      t = d / v

      t1 = x1 / v1

      t2 = x2 / v2

      t1 = 16090/22

      t1 = 731.36 s

      t2 = 16090/30

      t2 = 536.33 s

      t all = t1 + t2

      t all = 731.36 +536.33

      t all = 1267.69 s

Having these values ​​we use the initial equation

      Vm = d / t

      Vm = 32180 /1267.69

      Vm = 25.38 m / s

The average car speed is   25.4 m/s

solniwko [45]3 years ago
5 0

Answer:

Explanation:

average speed more than 25.0m/s.

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melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

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i)

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

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we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

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a = 22500 km/h²

Therefore,  the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

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300 = 0 + 22500 × t

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t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

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F = 360,000 kg × 1.736 m/s²

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F = 625 kN

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The emf induced in the second coil is given by:

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Plug in and solve for V:

V = -32×10⁻³(-1.0×10⁴e^(-2.0×10³t))

V = 320e^(-2.0×10³t)

We want to find the induced emf right after the current starts to decay. Plug in t = 0s:

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zaharov [31]

Answer:

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Variation of Z with respect to υ is shown in the figure.

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