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Greeley [361]
3 years ago
8

In motion pictures, what do you call the lens manipulation where the focus quickly changes from one subject to the next in a mot

ion picture
Physics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

A film transition is a technique used in the post-production process of film editing and video editing by which scenes or shots are combined. Most commonly this is through a normal cut to the next shot. Most films will also include selective use of other transitions, usually to convey a tone or mood, suggest the passage of time, or separate parts of the story. These other transitions may include dissolves, L cuts, fades (usually to black), match cuts, and wipes.

Explanation:

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A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular spe
kipiarov [429]

The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [ μ₀ ωqR² ] / [2.5(√5)πR ].

The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.

The radius of the nonconducting ring is R.

The ring is uniformly charged q.

The angular speed of the ring is ω.

The ring is x = (1/2)R from the center of the ring.

The magnetic field on the axis of a current loop is given as:

B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]

Now, I = q / [2π/ω]

When x = R/2 the magnitude of the magnetic field is:

B = [ μ₀ ωqR² ] / [4π( x² + R²)^{3/2} ]

B = [ μ₀ ωqR² ] / [4π( ( R/2 )² + R² )^{3/2} ]

B = [ μ₀ ωqR² ] / [4π( [5/4]R² )^{3/2} ]

B = [ μ₀ ωqR² ] / [2.5(√5)πR ]

Learn more about the magnetic field here:

brainly.com/question/14411049

#SPJ4

6 0
2 years ago
Determine the direction of the force (if any) that will act on the charge in each of the following situations. A positive charge
NeTakaya

Answer:

a) F on the right , b)    F up , c) Force to the left , d)  Force down , e)  Force towards the screen , f) Force is zero

Explanation:

The equations for the forces are

Electric

          F = q E

Magnetic

          F = q v x B

The Bold are vectors, the charges are positive

Let's apply these equation to the proposed situations

a) as the load is positive the force goes in the direction of the field

      F on the right

b) as the load is negative the force goes in the opposite direction to the field

     F is up

c) positive charge with speed down and magnetic field out of the screen.

For this part we will use the right hand rule. The thumb is in the direction of the speed, the fingers extended in the direction of the magnetic field and the palm is in the direction of the force for a positive charge

       Force to the left

d) negative charge, speed to the right magnetic field between the screen

   The force has direction

      Force down

e) positive charge, electric field towards the screen.

     Force in the direction of the field

        Force towards the screen

.f) negative charge, speed to the right, magnetic field to the right

    The vector product is zero,

     Force is zero

3 0
3 years ago
What happens to mechanical energy if the potential energy of an object decreases?
OleMash [197]

D. Mechanical energy remains unchanged.

Mechanical energy = Potential energy + Kinetic energy

So if potential energy decreases, then kinetic energy must increase so that the system is balanced.

6 0
3 years ago
Differences between distance and displacement.​
fiasKO [112]
It is a vector quantity
7 0
4 years ago
11 .As you are sitting in your chair the force of gravity is pulling you down. What force is causing you to stay in the chair in
Olin [163]

Answer:B

Explanation:

As you are sitting on the chair, gravity tends to pull you downwards but the normal reaction exerted by the chair is just enough to keep you from falling downwards. It works in the upward direction

5 0
3 years ago
Read 2 more answers
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