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Greeley [361]
2 years ago
8

In motion pictures, what do you call the lens manipulation where the focus quickly changes from one subject to the next in a mot

ion picture
Physics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

A film transition is a technique used in the post-production process of film editing and video editing by which scenes or shots are combined. Most commonly this is through a normal cut to the next shot. Most films will also include selective use of other transitions, usually to convey a tone or mood, suggest the passage of time, or separate parts of the story. These other transitions may include dissolves, L cuts, fades (usually to black), match cuts, and wipes.

Explanation:

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An object is held at an unknown height above Earth’s surface, where the acceleration due to gravity of the object is considered
Aleks04 [339]

Answer:

Options A and B.

Explanation:

Gravitational acceleration, initial height, intial speed and time are required to determine final speed. The option D is incorrect, since speed varies in time. Option C is dimentionally wrong.

The correct strategy is calculating the initial height from option B. Later, substituting time in equation A to derive an expression of the final velocity in terms of position. Hence, the required equations are options A and B.

7 0
3 years ago
Air pressure is 1.0 · 105 N/m2, air density is 1.3 kg/m3, and the density of soft drinks is 1.0 · 103 kg/m3. If one blows carefu
natita [175]

Answer:

v = 27.456 m/s

Explanation:

The support pressure needed of the water in the straw can be calculated by the formula

Given that,

P = r*g*h

= 1000*9.8*0.05 Pa.= 490 Pa

This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

velocity of air blown into the straw =

v = 27.456 m/s

8 0
3 years ago
Which of the following should a warm up NOT include?
Arlecino [84]
The answer to this is ax
7 0
3 years ago
What is 12 and 1 half % expressed as a fraction
kiruha [24]
12 1/2 i would assume
6 0
3 years ago
Read 2 more answers
A 1280 kg car is moving 4.92 m/s. a 509 N force then pushes it forward for 28.7 m. what is its final KE?(unit=J)PLEASE HELP
laila [671]

Answer:

The answer to your question is: total energy = 30100.4 J

Explanation:

Kinetic energy (KE) is the energy due to the movement of and object, its units are joules (J)

Data

mass = 1280 kg

speed = 4.92 m/s

Force = 509 N

distance = 28.7 m

Formula

KE = \frac{1}{2} mv^{2}

Work = Fd

Process

- Calculate Kinetic energy

- Calculate work

- Add both results

KE = \frac{1}{2} (1280)(4.92)^{2}

KE = 15492.1 J

Work = (509)(28.7)

Work = 14608.3 J

Total = 15492.1 + 14608.3

Total energy = 30100.4 J        

8 0
3 years ago
Read 2 more answers
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