Answer: 10.3m/s
Explanation:
In theory and for a constant velocity the physics expression states that:
Eq(1): distance = velocity times time <=> d = v*t for v=constant.
If we solve Eq (1) for the velocity (v) we obtain:
Eq(2): velocity = distance divided by time <=> v = d/t
Substituting the known values for t=15s and d=155m we get:
v = 155 / 15 <=> v = 10.3
1. What is the force of the marble?
For an object near the surface of the earth, the gravitational force acting upon the object is given by:
F = mg
F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.
Given values:
m = 0.025kg, g = 9.8m/s²
Plug in the given values and solve for F:
F = 0.025×9.8
F = 0.25N
2. What is the marble's potential energy at the start of its fall?
The gravitational potential energy of an object near the earth's surface is given by:
PE = mgh
PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.
new given values:
h = 0.08m
Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:
PE = F×h
PE = 0.25×0.08
PE = 0.02J
Answer:
Speed, v = 312.34 m/s
Explanation:
The equation that describes a transverse wave on the string is given by :
![y=0.0120\ msin[(927\ rad/s)t-(3\ rad/m)x]](https://tex.z-dn.net/?f=y%3D0.0120%5C%20msin%5B%28927%5C%20rad%2Fs%29t-%283%5C%20rad%2Fm%29x%5D)
..............(1)
Where
y = displacement of a string particle
x = position of the particle on the string
The wave is travelling in the +x direction. We have to find the speed of the wave.
The general equation of traverse wave is given by :
................(2)
On comparing equation (1) and (2) we get,
k = 3 rad/m
Since, 
..............(3)
Also, 
Since, 
...............(4)
Speed of the wave is the product of frequency and wavelength i.e.
Using equation (3) and (4), the speed of the wave can be calculated as :
v = 312.34 m/s
Hence, the speed of the transverse wave is 312.34 m/s
The answer is 30 ... same as the Atomic number.
Explanation:
Ultraviolet is a form of electromagnetic radiation with wavelength from 10 nm to 400 nm, shorter than that of visible light, but longer than X-rays. UV radiation is present in sunlight, and constitutes about 10% of the total electromagnetic radiation output from the Sun.
