Two railroad cars, each of mass 6500 kg and traveling 80 km/h in opposite directions, collide head-on and come to rest. how much
1 answer:
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Complete Question
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is
Explanation:
From the question we are told that
The mass of the steel ball is
The length of arm is
The mass of the arm is
Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as
=>
=>
Generally the magnitude of torque about the athlete shoulder is mathematically represented as
=>
=>
<u>Answer:</u>
Lead
<u>Explanation:</u>
To get the density of the material, the formula would be:
mass divided by volume which is given by .
Here in this problem, we are given a mass of which occupies a volume of
.
So plugging the data in the above formula to find the density:
Density =
From the table, we can see that the material is Lead which has a density of 11.3c/cm^3.
Answer:
Power will be 0.2023 watt
And when amplitude is halved then power will be 0.0505 watt
Explanation:
We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg
Length of wire l = 84 cm = 0.84 m
So mass density
Tension in the wire T = 25 N
Frequency f = 120 Hz
So angular frequency
And amplitude A = 1.6 mm = 0.0016 m
We have to find the generated power
Power is given by
From the relation we can see that power
So if amplitude is halved then power will be times
So power will be equal to