Answer:
v = 120 m/s
Explanation:
We are given;
earth's radius; r = 6.37 × 10^(6) m
Angular speed; ω = 2π/(24 × 3600) = 7.27 × 10^(-5) rad/s
Now, we want to find the speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator.
The angle will be;
θ = ¾ × 90
θ = 67.5
¾ is multiplied by 90° because the angular distance from the pole is 90 degrees.
The speed of a point on the earth's surface located at 3/4 of the length of the arc between the equator and the pole, measured from equator will be:
v = r(cos θ) × ω
v = 6.37 × 10^(6) × cos 67.5 × 7.27 × 10^(-5)
v = 117.22 m/s
Approximation to 2 sig. figures gives;
v = 120 m/s
Answer:
See the explanation below.
Explanation:
If you connect the three bulbs 20 W each will have a total power of 60W.
Now we need to understand to assign the meaning of the word gap, that is, if the circuit is open at that point or if there is no bulb connected at that point.
If the circuit is open at Point 2, there will be no current in the circuit, so the battery will drain faster with the three bulbs 20W.
In the second event, where gap means that there are no bulbs connected at that point, it means that you have two bulbs connected in series of 80W each.
In this case the bulbs will consume 160W thus drain the battery faster than the three 20W bulbs connected in series.
