Who created the planetary model of the atom?

What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?

worty [1.4K]

B. This is because the Hydrogen and Oxygen need balanced out.

Current-

C-1 | C-1
H-4 | H-2
O-2 | O-3

Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

CH4 + 2O2 → CO2 + 2H2O
C-1 | C-1
H-4 | H-4
O-4 | O-4

4 0

3 years ago

the combustion of a sample butane, C4H10 (lighter fluid) produced 2.46 grams of water. how many moles of water formed

enyata [817]

$2C_4H_{10}+13O_2$ ⇒ $8CO_2 + 10H_2O$

$n= \frac{m}{M} = \frac{m}{2M(H)+M(O)}= \frac{2,46}{2*1,0+16,0} = 0,14mol$

So 0,14mol are formed.

6 0

3 years ago

3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution that freezes at −4. 5∘c. what is the molar mass of

enyata [817]

3. 4 g of a nonelectrolyte dissolved in 78. 3 g of water produces a solution. The molar mass of the solute will be 17.94.

<h3>What is molar mass?</h3>

Molar mass of a substance is its mass in grams in per mole of a solution.

Freezing point: Freezing point of a substance is a temperature at which a liquid starts to solidify.

Depression in the freezing point can be calculated

[Depression in freezing point of pure solvent—Freezing point of solution] =[(0) - (-4.5)] °C =4.5 °C

molar mass = Number of moles of solute m / Mass of solvent in Kg

3.4g / M x 1/ 0.0783 kg = 43.42

Substitute AT by 4.5°C , Kr by 1.86 °C/m, and m by 43.42 m in equation (1) as follows:

1.86 x 43.42 / 4.5 = 17.94

Therefore, molar mass of solute to be 17.94.

To learn more about molar mass, refer to the link:

brainly.com/question/22997914

#SPJ4

4 0

1 year ago

Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen

bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=13mol × 1mol

2mol

x= 13mol

2mol

x= 6.5mol of oxygen

6 0

1 year ago

When solving a problem it is important to identify your given and needed units, but it is also important to understand the relat

UNO [17]

Answer:

See Explanation

Explanation:

Given

(a) to (d)

Required

Determine whether the given parameters can calculate the required parameter

To calculate either Density, Mass or Volume, we have

$Density = \frac{Mass}{Volume}$

$Mass = Density * Volume$

$Volume = \frac{Mass}{Density}$

(a) 432 g of table salt occupies 20.0 cm^3 of space

Here, we have:

$Mass = 432g$

$Volume = 20.0cm^3$

The above can be used to calculate Density as follows;

$Density = \frac{Mass}{Volume}$

$Density = \frac{432g}{20.0cm^3}$

$Density = 21.6g/cm^3$

(b) 5.00 g of balsa wood, density of balsa wood : 0.16 g/cm^3

Here, we have:

$Mass = 5.00g$

$Density = 0.16g/cm^3$

This can be used to solve for Volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{5.00g}{0.16g/cm^3}$

$Volume = 31.25cm^3$

(c) 32 cm^3 sample of gold density of 19.3 g/cm^3

Here, we have:

$Volume = 32cm^3$

$Density = 19.3g/cm^3$

This can be used to calculate Mass as follows:

$Mass = Density * Volume$

$Mass = 32cm^3 * 19.3g/cm^3$

$Mass = 617.6g$

(d) 150 g of iron, density of Iron = 79.0 g/cm^3

Here, we have

$Mass = 150g$

$Density = 79.0g/cm^3$

This can be used to calculate volume as follows:

$Volume = \frac{Mass}{Density}$

$Volume = \frac{150g}{79.0g/cm^3}$

$Volume = 1.90 cm^3$ Approximated

5 0

2 years ago