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ElenaW [278]
3 years ago
8

A 20.0 % by mass solution of phosphoric acid (H 3PO 4) in water has a density of 1.114 g/mL at 20°C. What is the molarity of thi

s solution?
Chemistry
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

2.28 M

Explanation:

Step 1: Given data

Percent by mass (%m/m): 20.0 %

Density (ρ): 1.114 g/mL

Step 2: Calculate the percent by volume (%m/v)

We will use the following expression.

\% m/v = \% m/m \times \rho = 20.0 \%  \times 1.114g/mL = 22.3 g \% mL

Step 3: Calculate the moles of solute in 100 mL of solution

The molar mass of phosphoric acid is 97.99 g/mol. The moles corresponding to 22.3 g are:

22.3g \times \frac{1mol}{97.99g} = 0.228mol

Step 4: Calculate the molarity of the solution

0.228 moles of solute are in 100 mL (0.100 L) of solution. The molarity of the solution is:

M = \frac{0.228mol}{0.100L} =2.28 M

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