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FinnZ [79.3K]
3 years ago
12

michael kicks a ball at an angle if 36* horizontal. its initial velocity is 46 m/s. Find the maximum height it can reach, total

time, and horizontal displacement for this motion
Physics
1 answer:
MAVERICK [17]3 years ago
3 0

(a) At its maximum height, the ball's vertical velocity is 0. Recall that

{v_y}^2-{v_{0y}}^2=2a_y\Delta y

Then at the maximum height \Delta y=y_{\mathrm{max}}, we have

-\left(\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

\implies y_{\mathrm{max}}=37\,\mathrm m

(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

v_y=v_{0y}+a_yt

and at its maximum height, v_y=0 so that

0=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ+\left(-9.8\,\dfrac{\mathrm m}{\mathrm s}\right)t

\implies t=2.8\,\mathrm s

which would mean the ball spends a total of about 5.6 seconds in the air.

(c) The ball's horizontal position in the air is given by

x=v_{0x}t

so that after 5.6 seconds, it will have traversed a displacement of

x=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\cos36^\circ(5.6\,\mathrm s)

\implies x=180\,\mathrm m

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goblinko [34]

Given Information:  

Wavelength of the red laser = λr = 632.8 nm

Distance between bright fringes due to red laser = yr = 5 mm

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Required Information:  

Wavelength of the laser pointer = λp = ?

Answer:

Wavelength of the laser pointer = λp = ?

Explanation:

The wavelength of the monochromatic light can be found using young's double slits formula,

y = Dλ/d  

y/λ = D/d

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λ is the wavelength

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d is the double slit separation distance

D is the distance from the slits to the screen

For the red laser,

yr/λr = D/d

For the laser pointer,

yp/λp = D/d

Equating both equations yields,

yr/λr = yp/λp

Re-arrange for λp

λp = yp*λr/yr

λp =  (5*632.8)/5.14

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Therefore, the wavelength of the small laser pointer is 615.56 nm.

3 0
3 years ago
Choose all facts that increase the orbital velocity of a vessel around planet B. Bigger mass of planet B smaller mass of planet
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Answer:

- Bigger mass of planet B  

- orbiting closer to planet B

Explanation:

The orbital velocity of the vessel around the planet can be found by equalizing the force of gravity between the vessel and the planet and the centripetal force:

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where

G is the gravitational constant

m is the mass of the vessel

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r is the distance between the vessel and the centre of the planet

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Re-arranging the formula, we find an expression for v:

v=\sqrt{\frac{GM}{r}}

We see that:

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So, the correct choices that increase the orbital velocity are:

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WARRIOR [948]

Answer:

y = 80.2 mille

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