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2 years ago

Find the value of x and thank for answer

Mathematics

1 answer:

lakkis [162]2 years ago

3 0

The value for x is 102 degrees

First we can find the second value in the triangle by subtracting 141 from 180. This works because when added together these two angles come together to from a line (180 degrees) because this value is now known (39 degrees) we can subtract both from 180:

180-39-39= x = 102

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PLEASE HELP, MATH, PLEASE<br>Solve for n: n+5/16 = -1

Anit [1.1K]

$\tt Step-by-step~explanation:$

To solve for n, we have to isolate n. To do so, we move all the terms that are not n to one side of the equation, and leave n on the other side.

$\tt Steps:$

Equation: n + 5/16 = -1

Subtract 5/16 on both sides to bring it to the right side of the equation.

$\tt n+5/16-5/16=-1-5/16\\\\n=-\frac{21}{16}~or~-1\frac{5}{16}$

$\Large\boxed{\tt Our~final~answer:~n=-\frac{21}{16}~or~-1\frac{5}{16} }$

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2 years ago

Please help me out!!! :)

Olin [163]

it would be > because the square root of 2 is more than 1.

8 0

3 years ago

Read 2 more answers

Write a quadratic function with zeroes 0 and 8.

Jlenok [28]

Answer:

$x^2-8x=0$

Step-by-step explanation:

the quadratic function should be as follows:

$x^2-8x=0$

Now let's confirm that the zeros of the function are 0 and 8

$x^2-8x=0=x(x-8)=0$

Therefore we can see that if x = 0

$0^2*8*0=0\\0=0$

the equation is fulfilled

And we also have $(x-8)$

for this expresion to be equal to zero:

$x-8=0\\x=8$

thus, if x = 8

$8^2-8*8=0\\64-64=0\\0=0$

the equation is also fulfilled

The zeros of the quadratic function $x^2-8x=0$ are 0 and 8.

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3 years ago

Special Right Trianglws

Masteriza [31]

Answer:

x = $2\sqrt7$

y = $2\sqrt7$

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by $\sqrt2$ .