When you solve the equation x^3-3x^2+2x=0, how many roots are greater than 1/2?

1 answer:

7 0

Hello :
<span>x^3-3x^2+2x=0
x(x²-3x+2) = 0
x(x-1)(x-2) = 0
x = 0 or x-1 = 0 or x-2= 0
x = 0 or x = 1 or x = 2
two </span><span>roots are greater than 1/2 : 1 and 2</span>

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