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sammy [17]
2 years ago
9

How many molecules Of H20 are equivalent to 97.2 g H20? (H = 1.008 g/mol, O = 16.00 g/mol)

Chemistry
1 answer:
AleksandrR [38]2 years ago
8 0

Answer:

m(H₂O) = 97,2 g.n(H₂O) = m(H₂O) ÷ M(H₂O).n(H₂O) = 97,2 g ÷ 18

Explanation:

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Answer:

The concentration of KBr is  C = 0.07899 \ mol   L^{-1}

Explanation:

From the question we are told that

      The mass of KBr is  m_{KBr}  = 2.35 \ g

       The molar mass of KBr is  M_{KBr} =  119 g/mol

       Volume of water is V = 250 \ mL = 250 *10^{-3} =  0.250 \ L

This implies that the volume of  the solution is  V = 250 mL

The number of moles of KBr is

         n = \frac{m_{KBr}}{M_{KBr}}

Substituting values

         n =  \frac{2.35}{119}

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The concentration of KBr is mathematically represented as

                C = \frac{0.01975}{0.250}

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