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Harrizon [31]
3 years ago
8

How many times greater is the value of the 2 of the 270413 than the valuce of the 2 in 419427?

Engineering
1 answer:
nadezda [96]3 years ago
7 0
The value of 2 in 270,413 is 10,000x greater than the value of 2 in 419,427.
Step-by-step explanation:
The value of 2 in 270,413 is 200,000.
The value of 2 in 419,427 is 20
Divide the two numbers together to find your answer:
200,000/20 = 10,000
The value of 2 in 270,413 is 10,000x greater than the value of 2 in 419,427.

Please mark it as brainlest answer:).
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Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5160 kJ/h for each kW of power it c
Mars2501 [29]

Answer:

COP_R=1.433\\Q_H=2.433kW

Explanation:

Hello,

In this case, the coefficient of performance of this refrigerator is defined in terms of the removed heat and the work input as:

COP_R=\frac{Q_{L}}{W_{in}} =\frac{5160\frac{kJ}{h}*\frac{1h}{3600s} }{1kJ/s} =1.433

Moreover, the rate of heat rejection to the outside air tuns out:

W_{in}=Q_H-Q_L\\Q_H=W_{in}+Q_L=1kW+5160\frac{kJ}{h}*\frac{1h}{3600s} =2.433kW

Best regards.

3 0
3 years ago
Read 2 more answers
5x−2y=30 Complete the missing value in the solution to the equation. (8, )
givi [52]

Answer:

Value of y = 5

(8,5)

Explanation:

Given:

5x−2y=30

Value of x = 8

Find:

Value of y

Computation:

⇒ 5x−2y=30

⇒ 5(8)−2y=30

⇒ 40−2y=30

⇒ -2y = -10

y = 5

Value of y = 5

(8,5)

4 0
3 years ago
I WILL GIVE 20 POINTS!!
Alex777 [14]

Answer:

Use a resume header

Explanation:

Create a Summary

Research industry, employer keywords

there are some hints okay

5 0
3 years ago
Read 2 more answers
thermo A large container ship is propelled by a heat engine that uses fuel oil as a heat source and sea water as a heat sink. Th
TEA [102]

Answer:

\eta = 4.617\times 10^{-4}\,(0.046\,\%), \dot Q_{out} = 162369.444\,kW

Explanation:

The definition of thermal efficiency follows to this expression:

\eta = \frac{\dot W}{\dot Q_{in}}

\eta = \frac{75\,kW}{\left(43000\,\frac{kJ}{L} \right)\cdot \left(13600\,\frac{L}{h} \right)\cdot \left(\frac{1\,h}{3600\,s}  \right)}

\eta = 4.617\times 10^{-4}\,(0.046\,\%)

The rate of heat transfer to the ocean is:

\dot Q_{out} = \dot Q_{in}-\dot W

\dot Q_{out} = \left(43000\,\frac{kJ}{L}  \right)\cdot \left(13600\,\frac{L}{h}  \right)\cdot \left(\frac{1\,h}{3600\,s}  \right)-75\,kW

\dot Q_{out} = 162369.444\,kW

3 0
4 years ago
A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled
Vikentia [17]

Answer:

Force per unit plate area is 0.1344 N/m^{2}

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, \mu =1.92\times 10^{- 3} Pa-s

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

F = \tau A

where

\tau = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = (\tau ' +\tau '')A

\frac{F}{A} = \tau ' +\tau ''

Also

F = \frac{\mu v}{d}

where

\mu = dynamic coefficient of viscosity

Pressure, P = \frac{F}{A}

Therefore,

\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}

\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}

8 0
3 years ago
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