Question

Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and a 1k ohm load are connected the DC output voltage is 14V. What is... The value of the capacitor? The value of the peak to peak ripple voltage?

Answer 1

Answer:

$V_{pp}=2V$

Explanation:

Source Voltage $V= 120V$

Frequency $f=60Hz$

Peak output voltage $Vp=15V$

Peak Output Voltage with filter $V_p'=14V$

Generally the equation for Peak to peak voltage is mathematically given by

$V_p'=V_p-\frac{V_{pp}}{2}$

Therefore

$V_{pp}=2(V_p-v_p')$

$V_{pp}=2(15-14)$

$V_{pp}=2V$