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2 years ago

1. Springs____ energy when compressed And _energy when they rebound.

Engineering

1 answer:

densk [106]2 years ago

6 0

Answer:

Springs store energy when compressed and release energy when they rebound

Explanation:

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A company buys a machine for $12,000, which it agrees to pay for in five equal annual payments, beginning one year after the dat

Yuki888 [10]

Answer:

$7,778.35

Explanation:

At year 3, the final payment of the remaining balance is equal to the present worth P of the last three payments.

First, calculate the uniform payments A:

A = 12000(A/P, 4%, 5)

= 12000(0.2246) = 2695.2 (from the calculator)

Then take the last three payments as its own cash flow.

To calculate the new P:

P = 2695.2 + 2695.2(P/A, 4%, 2) = 2695.2 + 2695.2(1.886) = 7778.35

Therefore, the final payment is $7,778.35

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3 years ago

What are the different types of documents used to communicate engineering designs?

Ipatiy [6.2K]

Answer:

COMMON ENGINEERING DOCUMENTS

Inspection or trip reports.

Research, laboratory, and field reports.

Specifications.

Proposals.

Progress reports.

ect...

Explanation:

7 0

3 years ago

A rigid tank contains 2 kg of N2 and 4 kg of Co2 at temperature of 25 C and 1 MPa. Find the partial pressure of each gas respect

lions [1.4K]

Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.

Explanation: Dalton's Law of Partial Pressure states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:

$P_{total} = P_{1}+P_{2}+...$

The proportion of each individual gas in the total pressure is expressed in terms of mole fraction:

$X_{i}$ = moles of a gas / total number moles of gas

The rigid tank has total pressure of 1MPa.

Nitrogen gas:

molar mass = 14g/mol

mass in the tank = 2000g

number of moles in the tank: $n=\frac{2000}{14}$ = 142.85mols

Carbon Dioxide:

molar mass = 44g/mol

mass in the tank = 4000g

number of moles in the tank: $n=\frac{4000}{44}$ = 90.91mols

Total number of moles: 142.85 + 90.91 = 233.76 mols

To calculate partial pressure:

$P_{i}=P_{total}.X_{i}$

For Nitrogen gas:

$P_{N_{2}}=1.\frac{142.85}{233.76}$

$P_{N_{2}}$ = 0.6

For Carbon Dioxide:

$P_{total}=P_{N_{2}}+P_{CO_{2}}$

$P_{CO_{2}} = P_{total}-P_{N_{2}}$

$P_{CO_{2}}=1-0.6$

$P_{CO_{2}}=$ 0.4

Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.

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2 years ago

Consider the following fragment of code in an authentication program:

Juli2301 [7.4K]

Answer:

Backdoor

Explanation:

The back door fragment in a program allows user to access backdoor information without necessarily following the common security procedures needed. In this case, once the programmer keys in the username he or she logs in without putting password. Therefore, this is a backdoor fragment.

8 0

3 years ago

Tech A says that the stoichiometric ratio is 14.7 gallons of air to 1 gallon of fuel. Tech B says it is 14.7 lb of air to 1 lb o

Degger [83]

The person that is correct as regards statement made about stoichiometric ratio is; Tech B

In air-fuel mixture, when there is a mix air and fuel in the ideal amounts to make an engine to run efficiently,the ideal ratio of air to fuel is known Stoichiometric ratio.

This stoichiometric ratio is the comparison between the weight of the air relative to the weight of the fuel that it has been mixed with.

Now, weight is in lb and as such, tech B is correct because his ratio is 14.7lb to 1 lb.

Read more at; brainly.com/question/16971089

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2 years ago

1. Springs____________ energy when compressed And _________energy when they rebound.

1. Springs____ energy when compressed And _energy when they rebound.