Explanation:
sorry I really need points so I can ask a question
The given questions belongs to the concept of limiting reagent.
The number of moles of carbon dioxide produced when 4.6 moles of dioxygen reacts is 4.6 moles.
<h3 /><h3>What is Limiting Reagent ?</h3>
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed.
Given ;
Moles of Oxygen = 4.6
To find;
Moles of Carbon di oxide = ?
The reaction that forms
is as follows:
C(s) +
(g) -->
(g)
This means that
is consumed and
is produced in a 1:1 ratio.
If we consume 4.6 mol
, then we produce 4.6 mol
.
Hence, 4.6 mol
are produced when 4.6 mol of oxygen reacts.
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Positron emission = emission of a positron and a neutrino when a
proton is convert into a neutron. The total number of particles in the
nucleus doesn't change, -1 proton +1 neutron
It's a spontaneous reaction for some nucleus.
eg:
Positron = e+
Neutrino=ve
O-15 --> N-15 + e+ +ve
Electron
capture= A nucleus absorb an electron while a proton is convert in a
neutron and emit a neutrino. The total number of particles in the
nucleus doesn't change, -1 proton +1 neutron
eg:
Al-26 +e- --> Mg-26 + ve
Electron
capture and positron emission are two mechanisms to explain the decay
of some unstable isotopes. Electron capture is usually observed when the
energy difference between the initial and final state is low. Mainly
because of the larger amount of kinetic energy need for the expulsion
two particles with the positron emission mechanism.
Electronic Configuration of Cu⁴⁺ is written using these two steps;
Step I:
Write the Electronic Configuration of Copper (Cu).
As Atomic Number of Cu = 29
So,
1s², 2s², 2p⁶, 3s², 3p⁶, 3d¹⁰, 4s¹
Rearranging it in order of increasing orbital energy,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s¹, 3d¹⁰
Or,
Cu = [Ar] 4s¹, 3d¹⁰
Step II:
Now, the Cu⁴⁺ ion has lost 4 electrons, So one electron from 4s and 3 electrons from 3d orbital are removed, The resulting electronic configuration becomes,
Cu⁴⁺ = [Ar] 3d⁷
At absolute zero the kinetic energy of the substance will be 0