Answer: B, the index fossils in the area of the bones.
(I do need 1 more brainliest to rank up, so if my answer is correct, that would be great, sorry if I sound rude.)
Answer:
This is achieved for the specific case when high quantum number with low resolution is present.
Step-by-step explanation:
In Quantum Mechanics, the probability density defines the region in which the likelihood of finding the particle is most.
Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.
To find the radius, then, we insert 18 in for the circumference. So 18=2∏r. Solving for r gives 9/∏, or approximately 2.86 inches.
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
-28
Step-by-step explanation:
Remember the order of operations: pemdas (<u>p</u>arenthesis, <u>e</u>xponent, <u>m</u>ultiply, <u>d</u>ivide, <u>a</u>dd, <u>s</u>ubtract). Just simplify the expression.
22 - 53 + 3
(22-53) + 3
-31 + 3
-28
