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kirill115 [55]
3 years ago
5

The formula for mustard gas used in chemical warfare is c4h8scl2 (159.09 g/mol). what is the percentage of hydrogen in the compo

und?
Chemistry
1 answer:
True [87]3 years ago
4 0
The molecular formula for mustard gas is C₄H₈SCl₂
the molecular mass of mustard gas - 159.09 g/mol
atomic mass of H is 1 g/mol
The mass of H in 1 mol of compound - 1 x 8 = 8 g
this means that in 159.09 g of compound , 8 g of H present 
mass percentage of hydrogen = 8 g/ 159.09 g x 100% 
mass percentage of hydrogen = 5.03%
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A 40-lb container of peat moss measures 14× 20× 30 in. A 40-lb container of topsoil has a volume of 1.9 gal. Calculate the avera
Viktor [21]

The average density of the peat moss in units of g/cm³ is 2.52 g/cm³

<h3>How to convert 40 lb to grams (g)</h3>

We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:

1 lb = 453.592 g

Therefore,

40 lb = (40 × 453.592) / 1 lb

40 lb = 18143.68 g

<h3>How to convert 1.9 gal to cm³</h3>

We can convert 1.9 gal to cm³ as follow:

1 gal = 3785.41 cm³

Therefore,

1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal

1.9 gal = 7192.279 cm³

<h3>How to determine the density </h3>

The density can be obtained as follow:

  • Mass = 18143.68 g
  • Volume = 7192.279 cm³
  • Density =?

Density = mass / volume

Density = 18143.68 / 7192.279

Density = 2.52 g/cm³

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brainly.com/question/952755

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8 0
2 years ago
How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?
Assoli18 [71]

Answer:

m_{Co^{3+}}=0.563gCo^{3+}

Explanation:

Hello there!

In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}

Best regards!

4 0
3 years ago
What is the difference between an element, compound and mixture?
Alex73 [517]
A compound is considered a pure substance meaning there is only one type of particle in the substance. A mixture is a combination of two or more different chemical pot compound or an element or substances. It is not a pure substance but I combination of multiple particles
6 0
3 years ago
Should the density of a metal depend on its volume?
jekas [21]

Answer:

Density is the ratio of the mass of an object to its volume. Density is an intensive property, meaning that it does not depend on the amount of material present in the sample. ... Since a cubic centimeter is equal to a milliliter, density units can also be expressed as g/mL.

Explanation:

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3 years ago
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Alex_Xolod [135]
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