1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalka [10]
3 years ago
7

Type the correct answer in the box. Spell all words correctly. In which system are both energy and matter exchanged with the sur

roundings? In a(n) system both energy and matter are exchanged with the surroundings.
​

Chemistry
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

open system

Explanation:

An open system is a system in which both energy and matter are exchanged with the surroundings.

You might be interested in
During an experiment, a scientist places a heat lamp above a bowl of water and uses the lamp to heat up the water. How does heat
dlinn [17]

Answer:

Radiation

Explanation:

6 0
3 years ago
Read 2 more answers
Granite is a ________ that contains the mineral quartz. a. mineral c. rock b. glass d. mica
kow [346]
I think it would be C

7 0
3 years ago
Read 2 more answers
Atoms of elements that are in group 15 with what charge
liq [111]

Answer:

The elements in group 13 and group 15 form a cation with a -3 charge each.

8 0
2 years ago
Pls help me ASAP thank you!!
Stolb23 [73]
Sorry i cant even read that
7 0
3 years ago
The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
Other questions:
  • Which of the following is a precipitation reaction?
    7·2 answers
  • How much has CO2 in the atmosphere increased since the Industrial<br> Revolution?
    12·1 answer
  • I need to do a project about carbon dioxide is there a safe way to capture it ??/
    12·1 answer
  • A student is participating in the school science fair. She wants to investigate household cleaners.
    7·2 answers
  • What is the oxidation number for Zn(OH)4 2-?
    5·1 answer
  • What is the mass of 2.15 liters of N2 gas at STP?
    5·2 answers
  • In a pure metal, the electrons can be thought of as [ Select ] throughout the metal. Using molecular orbital theory, there [ Sel
    7·1 answer
  • Answering just one is fine. Please help. It's due in less than an hour
    6·2 answers
  • Both graphite and pure metals are both soft. explain why
    10·1 answer
  • Why are alkali metals so reactive?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!