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omeli [17]
3 years ago
5

The density of an unknown gas is found to be 4.12 g/L at standard temperature and pressure (STP). What is the molar mass of this

gas?
Chemistry
2 answers:
elena-s [515]3 years ago
7 0
The   molar  mass of this gas  is  92.3 g/mol

  Calculation

By  use  ideal gas  equation PV =nRT  where
n=mole  p=pressure V= volume R =  gas constant  T=  temperature

n =  mass /molar  mass(MM)
substitute in the equation

PV =(mass/MM)RT
mass = density  x  volume(V)

Therefore  PV =(density xV/ MM) xRT

divide both side by  by V

P=  (density/Mm) xRT

making MM  the subject  of the formula

MM = densityPRT

At  STP = P= 1 atm,  R=  0.0821 L.atm/Mol.k  T =  273 K

MM is therefore = 4.12 g/l x   1 atm x 0.081  L.atm/mol.k  x    273 K = 92.3 g/mol

hichkok12 [17]3 years ago
7 0
At standard temperature and pressure, 1 mole of any gas occupies 22.4 litres. We need to find the number of grams in 22.4 litres of the unknown gas.

4.12 g/L * 22.4 = <span>92.288. 

</span><span>92.288 or 92 grams are in one mole of the gas making the molar mass 92 g/mole. </span>
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A 70.-kg person exposed to ⁹⁰Sr absorbs 6.0X10⁵ β⁻ particles, each with an energy of 8.74X10⁻¹⁴ J.(c) What is the equivalent dos
postnew [5]

A 70.-kg person exposed to ⁹⁰Sr absorbs 6.0X10⁵ β⁻ particles, each with an energy of 8.74X10⁻¹⁴ J.

<h3>What is β⁻ particles ?</h3>

A beta particle, also known as a beta ray or beta radiation (symbol ), is a highly energetic, swiftly moving electron or positron that is released during the radioactive disintegration of an atomic nucleus. Beta decay occurs in two ways: decay and + decay, which result in the production of electrons and positrons, respectively.

In air, beta particles with an energy of 0.5 MeV have a range of roughly one meter; the range is energy-dependent.

Ionizing radiation of the sort known as beta particles is regarded, for the purposes of radiation protection, as being more ionizing than gamma rays but less ionizing than alpha particles. The damage to live tissue increases as the ionizing effect increases, but so does the radiation's penetration power.

To learn more about β⁻ particles from the given link:

brainly.com/question/10111545

#SPJ4

7 0
1 year ago
Which of the following is the correct formula used for calculating Speed?
MAXImum [283]

Answer:

A- Speed = distance/time

Explanation:

Would make sense and that's what I remember

3 0
3 years ago
What is the precent yield if the actual yield is 25g and 100g should have formed?
11Alexandr11 [23.1K]

Answer:

Percent yield is 25%

Explanation:

Information given is

Actual yield is 25 g

But the yield should be 100 g

The percent yield is defined as the ratio of the actual yield and the predicted yield it means that out of the predicted yield what percentage of the actual yield is obtained

∴ Percent yield = (Actual yield ÷ Predicted yield) ×  100

In case of the given problem the percent yield will be

(25÷100) × 100 = 25%

∴ Percent yield = 25%

3 0
3 years ago
What NaCl NaCl concentration results when 249 mL 249 mL of a 0.850 M 0.850 M NaCl NaCl solution is mixed with 667 mL 667 mL of a
tamaranim1 [39]

Answer:

The answer to your question is 0.54M

Explanation:

Data

Final concentration = ?

Concentration 1 = 0.850 M

Volume 1 = 249 ml = 0.249 l

Concentration 2 = 0.420 M

Volume 2 = 0.667 M

Process

1.- Calculate the number of moles in both solutions

Number of moles 1 = Molarity 1 x Volume 1

                               = 0.850 x 0.249

                               = 0.212

Number of moles 2 = Molarity 2 x Volume 2

                                = 0.420 x 0.667

                                = 0.280

Total number of moles =  0.212 + 0.280

                                      = 0.492

2.-Calculate the final volume

Final volume = Volume 1 + Volume 2

Final volume = 0.249 + 0.667

                      = 0.916 l

3.- Calculate Molarity

Molarity = 0.492 / 0.916

Molarity = 0.54

4 0
3 years ago
This patient has a bone density of 820mg/cm3. What is the volume of a 25g sample?
mamaluj [8]

<u>Answer:</u> The volume of bone for given sample is 30.49cm^3

<u>Explanation:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of bone = 820mg/cm^3=0.82g/cm^3      (Conversion factor:  1 g = 1000 mg)

Mass of bone = 25 g

Putting values in above equation, we get:

0.82g/cm^3=\frac{25g}{\text{Volume of bone}}\\\\\text{Volume of bone}=30.49cm^3

Hence, the volume of bone for given sample is 30.49cm^3

3 0
3 years ago
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