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omeli [17]
3 years ago
5

The density of an unknown gas is found to be 4.12 g/L at standard temperature and pressure (STP). What is the molar mass of this

gas?
Chemistry
2 answers:
elena-s [515]3 years ago
7 0
The   molar  mass of this gas  is  92.3 g/mol

  Calculation

By  use  ideal gas  equation PV =nRT  where
n=mole  p=pressure V= volume R =  gas constant  T=  temperature

n =  mass /molar  mass(MM)
substitute in the equation

PV =(mass/MM)RT
mass = density  x  volume(V)

Therefore  PV =(density xV/ MM) xRT

divide both side by  by V

P=  (density/Mm) xRT

making MM  the subject  of the formula

MM = densityPRT

At  STP = P= 1 atm,  R=  0.0821 L.atm/Mol.k  T =  273 K

MM is therefore = 4.12 g/l x   1 atm x 0.081  L.atm/mol.k  x    273 K = 92.3 g/mol

hichkok12 [17]3 years ago
7 0
At standard temperature and pressure, 1 mole of any gas occupies 22.4 litres. We need to find the number of grams in 22.4 litres of the unknown gas.

4.12 g/L * 22.4 = <span>92.288. 

</span><span>92.288 or 92 grams are in one mole of the gas making the molar mass 92 g/mole. </span>
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Which of the following is true of the energy levels of electrons in shells?
anyanavicka [17]

Answer:

Option C is the correct. Valence electrons have a higher energy level than those in other filled shells

Explanation:

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The electrons always win energy to move from the first to the second shell.

All the electrons in an atom have similar energy levels FALSE.

They are not neccesary similar. In hydrogen these are the level energy -13.6 eV , -3.4 eV , -1.51 eV , -85 eV  and -54 eV

Electrons do not have potential energy, just kinetic energy. FALSE

They have both.

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8 0
3 years ago
Two unknown compounds are tested. Compound 1 contains 15.0g of hydrogen and 120.0g of oxygen. Compound 2 contains 2.0g of hydrog
ivann1987 [24]

Answer:

The both compounds are different.

Explanation:

In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.

Given data:

For compound 1.

Mass of hydrogen = 15 g

Mass of oxygen = 120 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol

Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol

Total number of moles = 22.5 mol

% of hydrogen = 15 /22.5 × 100 = 66.7%

% of oxygen = 7.5 / 22.5× 100 = 33.3%

For compound 2:

Mass of hydrogen = 2 g

Mass of oxygen = 32 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol

Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol

Total number of moles = 4 mol

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7 0
3 years ago
What is the volume, in liters, of 6.8 mol of Kr gas at STP?
Virty [35]

Answer:

\boxed {\boxed {\sf D. \ 152 \ L}}

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

Multiply both sides of the equation by 6.8 moles of krypton.

6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

The units of moles of krypton will cancel.

6.8 *\frac {22.4 \ L \ Kr}{1 }

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

68 * 22.4 \ L \ Kr

152.32 \ L \ Kr

If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

152 \ L \ Kr

6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.

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