Answer:
Here's what I get.
Explanation:
According to Markovnikov's rule, the H will add to a terminal carbon, generating three resonance stabilized carbocations.
The Br⁻ ion will add to any of the three carbocations.
There are three possible products:
- 5-bromo-2,5-dimethylhexa-1,3-triene (1)
- 3-bromo-2,5-dimethylhexa-1,4-triene (<em>2</em>)
- 1-bromo-2,5-dimethylhexa-2,4-triene (3)
