Answer:
Helps to accurately calculate job costs
Explanation:
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Answer:
2.77mpa
Explanation:
compressive strength = 20 MPa. We are to find the estimated flexure strength
We calculate the estimated flexural strength R as
R = 0.62√fc
Where fc is the compressive strength and it is in Mpa
When we substitute 20 for gc
Flexure strength is
0.62x√20
= 0.62x4.472
= 2.77Mpa
The estimated flexure strength is therefore 2.77Mpa
Answer:
B
Explanation:
A robot's work envelope is its range of movement. It is the shape created when a manipulator reaches forward, backward, up and down. These distances are determined by the length of a robot's arm and the design of its axes. ... A robot can only perform within the confines of this work envelope.
<h2>Answer:</h2>
<h3>Required Answer is as follows :-</h3>
- 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²
- ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²
- ¾ = m₁ × (V)²/m₂ × (V²/4)
<h3>Now,</h3>
- ∆m = m₂ - m₁
- ∆m = 16m₂/3 - m₁ = 13m₁/3
- Ratio = (13m₁/3)/ m₁
- Ratio = 13/3
Ratio = 13:3
<h3>Know More :-</h3>
Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.
