Answer:
8 mm
Explanation:
Given:
Diameter, D = 800 mm
Pressure, P = 2 N/mm²
Permissible tensile stress, σ = 100 N/mm²
Now,
for the pipes, we have the relation as:
where, t is the thickness
on substituting the respective values, we get
or
t = 8 mm
Hence, the minimum thickness of pipe is 8 mm
Answer:
Cloud computing services are going to be very important to supporting Ashville's mobile app since it has different uses. These applications uses include; data storage, as well as helping to provide network to any business data related work. This will improve the city of Ashville's mobile app operations considerably.
The benefits of using cloud computing are; it allows a business managers to be more concerned with running the business themselves rather than maintaining the data center. The use of cloud computing allows a company's IT administrators to focus on managing the company's operations, thereby allowing performance to be enhanced of the business enterprise.
A commercial company is able to create new technologies more rapidly with the use of cloud computing. Furthermore, the enterprise will be able to automate its activities using cloud computing. Cloud computing is also very important as it is more affordable and thus promotes the company's growth in the market. Cloud computing is also enhancing the global presence of the Ashville mobile app. The drawbacks of using cloud computing include the following; due to using the cloud infrastructure, the company's performance may be unreliable. People believe that cloud computing is not reliable and that cloud computing may not be secure at last and can't always be right for all workloads.
Explanation:
Answer:
The number of inputs processed by the new machine is 64
Solution:
As per the question:
The time complexity is given by:

where
n = number of inputs
T = Time taken by the machine for 'n' inputs
Also
The new machine is 65 times faster than the one currently in use.
Let us assume that the new machine takes the same time to solve k operations.
Then
T(k) = 64 T(n)


k = 64n
Thus the new machine will process 64 inputs in the time duration T
Answer:
(N-1) × (L/2R) = (N-1)/2
Explanation:
let L is length of packet
R is rate
N is number of packets
then
first packet arrived with 0 delay
Second packet arrived at = L/R
Third packet arrived at = 2L/R
Nth packet arrived at = (n-1)L/R
Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R
Now
L / R = (1000) / (10^6 ) s = 1 ms
L/2R = 0.5 ms
average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2
the average queuing delay of a packet = 0 ( put N=1)