The watts that are consumed is 80 watts.
<h3>What power factor?</h3>
The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.
Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have; V × I × PF = 100V × 4A × 0.2 = 80 watts.
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Complying with DSEAR involves:
Assessing risks. ...
Preventing or controlling risks. ...
Control measures. ...
Mitigation. ...
Preparing emergency plans and procedures. ...
Providing information, instruction and training for employees. ...
Places where explosive atmospheres may occur ('ATEX' requirements)
hse uk
The following is a feedback mechanism for a system :
<u>The progress bar when downloading a file on iTunes</u>
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Explanation:
- A feedback mechanism is a loop system wherein the system responds to a perturbation. The response may be in the same direction (as in positive feedback) or in the opposite direction (as in negative feedback).
- Feedback occurs when outputs of a system are routed back as inputs as part of a chain of cause-and-effect that forms a circuit or loop. The system can then be said to feed back into itself.
- Evaluation feedback needs to be done “in the moment” to help the person receiving the feedback know where they stand.
- A feedback control system consists of five basic components: (1) input, (2) process being controlled, (3) output, (4) sensing elements, and (5) controller and actuating devices.
- Because negative feedback produces stable circuit responses, improves stability and increases the operating bandwidth of a given system, the majority of all control and feedback systems is degenerative reducing the effects of the gain.
Answer:
There are 2 expected readings greater than 2.70 V
Solution:
As per the question:
Total no. of readings, n = 60 V
Mean of the voltage, 
standard deviation, 
Now, to find the no. of readings greater than 2.70 V, we find:
The probability of the readings less than 2.70 V, 
:
Now, from the Probability table of standard normal distribution:
Now,
Now, for the expected no. of readings greater than 2.70 V:
No. of readings expected to be greater than 2.70 V = 
No. of readings expected to be greater than 2.70 V = 
≈ 2
Answer:
Always make sure that you are properly protected and that it is all clear to be operated on.
