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bonufazy [111]
3 years ago
15

Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1200 K to a cold reservoir at 600 K. Calculate the

entropy change of the two reservoirs and determine if the increase of entropy principle is satisfied.
Engineering
1 answer:
Fantom [35]3 years ago
8 0

Solution:

Given:

T_{H} = 1200 K

T_{L} = 600 K

Q = 100 kJ

The Entropy change of the two reservoirs is given by the sum of entropy change of each reservoir system and is given by the formula:

\Delta s = \frac{-Q}{T_{H}}+\frac{Q}{T_{L}}

\Delta s = \frac{Q(T_{L}-T_{_{H}})}{T_{H}T_{L}}

\Delta s = \frac{-100(600-1200)}{1200\times 600}

[tex]\Delta s = 0.0833kJ/K

Since, the change in entropy is positive and according to the Increase in entropy principle, for any process the total change in entropy of a system is always greater than or equal to zero (with its enclosing adiabatic surrounding).

Therefore, the entropy principle is satisfied.

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In the construction of a large reactor pressure vessel, a new steel alloy with a plane strain fracture toughness of 55 MPa-m1/2
sp2606 [1]

Answer:

l=24mm

Explanation:

From the question we are told that:

Plane strain fracture toughness of T=55 MPa-m1/2

Y value Y=1.0

Stress level of\sigma =200 MPa

Generally the equation for length of a surface crack is mathematically given by

l=\frac{1}{\pi}(\frac{T}{Y*\sigma})^2

l=\frac{1}{3.142}(\frac{55}{1*200})^2

l=0.024m

Therefore

in mm

l=24mm

6 0
2 years ago
A slab-milling operation is performed on a 0.7 m long, 30 mm-wide cast-iron block with a feed of 0.25 mm/tooth and depth of cut
denis23 [38]

Answer:

a)  T_m=1.787min

b)  MRR=35259.7mm^3/min

Explanation:

From the question we are told that:

Cast-iron block Dimension:

Lengthl=0.7m=>700mm

Width w=30mm

FeedF=0.25mm/tooth

Depth dp=3mm

Diameter d=75mm

Number of cutting teeth n=8

Rotation speed N=200rpm

Generally the equation for Approach is mathematically given by

x=\sqrt{Dd-d^2}

X=\sqrt{75*3-3^2}

X=14.69mm

Therefore

Effective length is given as

L_e=Approach +object Length

L_e=700+14.69

L_e=714.69mm

a)

Generally the equation for Machine Time is mathematically given by

T_m=\frac{L_e}{F_m}

Where

F_m=F*n*N

F_m=0.25*8*200

F_m=400

Therefore

T_m=\frac{714.69}{400}

T_m=1.787min

b)

Generally the equation for Material Removal Rate. is mathematically given by

MRR=\frac{L*B*d}{t_m}

MRR=\frac{700*30*3}{1.787}

MRR=35259.7mm^3/min

3 0
3 years ago
A solid cylindrical workpiece made of 304 stainless steel is 150 mm in diameter and 100 mm is high. It is reduced in height by 5
goblinko [34]

Answer:

45.3 MN

Explanation:

The forging force at the end of the stroke is given by

F = Y.π.r².[1 + (2μr/3h)]

The final height, h is given as h = 100/2

h = 50 mm

Next, we find the final radius by applying the volume constancy law

volumes before deformation = volumes after deformation

π * 75² * 2 * 100 = π * r² * 2 * 50

75² * 2 = r²

r² = 11250

r = √11250

r = 106 mm

E = In(100/50)

E = 0.69

From the graph flow, we find that Y = 1000 MPa, and thus, we apply the formula

F = Y.π.r².[1 + (2μr/3h)]

F = 1000 * 3.142 * 0.106² * [1 + (2 * 0.2 * 0.106/ 3 * 0.05)]

F = 35.3 * [1 + 0.2826]

F = 35.3 * 1.2826

F = 45.3 MN

7 0
3 years ago
What are some "vital signs" that we consider to tell us about the economy?
Wittaler [7]

Explanation:

if there is a deficit or a surplus

if the budget is good

7 0
3 years ago
Read 2 more answers
A 3.52 kg steel ball is tossed upward from a height of 6.93 meters above the floor with a vertical velocity of 2.99 m/s. What is
Dafna1 [17]

Answer : The final velocity of the ball is, 12.03 m/s

Explanation :

By the 3rd equation of motion,

v^2-u^2=2as

where,

s = distance covered by the object = 6.93 m

u = initial velocity  = 2.99 m/s

v = final velocity = ?

a = acceleration = 9.8m/s^2

Now put all the given values in the above equation, we get the final velocity of the ball.

v^2-(2.99m/s)^2=2\times (9.8m/s^2)\times (6.93m)

v=12.03m/s

Thus, the final velocity of the ball is, 12.03 m/s

7 0
3 years ago
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