Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:
AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°( )}
AD ≅ CD ....……….{ }
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
4x² - 25 = 0
4x² - 10x + 10x - 25 = 0
2x(2x) - 2x(5) + 5(2x) - 5(5) = 0
2x(2x - 5) + 5(2x - 5) = 0
(2x + 5)(2x - 5) = 0
2x + 5 = 0 U 2x - 5 = 0
- 5 - 5 + 5 + 5
2x = -5 2x = 5
2 2 2 2
x = -2¹/₂ x = 2¹/₂
Solution Set: {-2¹/₂, 2¹/₂}
D /////////////////////////////