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Troyanec [42]
3 years ago
6

What is specific gravity​

Physics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

It is the ratio of the density of a substance to the density of a given reference material.

Explanation:

<em>Specific gravity is also known as relative density.</em>

<u>To find the relative density of substance, you:</u>

  • Divide the density of substance measured
  • And divide that by the density of the reference

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17.Explain the different ways that an object can become electrically charged.
Debora [2.8K]

17.

There are three different methods for charging objects:

- Friction: in friction, two objects are rubbed against each other. As a result, electrons can be passed from one object to the other, so one object will gain a net negative charge while the other object will gain a net positive charge due to the lack of electrons.

- Conduction: this occurs when two conductive objects are put in contact with each other, and charges (electrons, usually) are transferred from one object to the other one.

- Induction: this occurs when two objects are brought closer to each other, but not in contact. If one of the two objects has a net charge (different from zero) on its surface, then it will induce a movement of charges in the second object: in particular, in the second object, charges of the opposite polarity will be attracted towards the first object, while charges of same polarity will be repelled further away.

18.

Charged objects produce around themselves an electric field. The strenght of the electric field is given by (assuming the charged objects are spherical)

E=k\frac{q}{r^2}

where k is the Coulomb's constant, q is the magnitude of the charge and r the distance from the centre of the charge. As we see, the strength of the field is inversely proportional to the square of the distance.

Also, the direction of the field is determined by the sign of the charge:

- if the charge is positive, the electric field points away from the charge (this means that other positive charges in the field will be repelled away)

- if the charge is negative, the electric field points towards the charge (this means that other positive charges in the field will be attracted towards it)

19.

Electrical force is given by:

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 are the two charges, and r their separation.

Gravitational force is given by:

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r their separation.

Similarities between the two forces:

- Both are inversely proportional to the square of the distance between the two objects, r

- Both are non-contact forces (the two objects can experience the forces even if they are not in contact)

- Both forces have infinite range

Differencies between the two forces:

- The electric force can be either attractive or repulsive, while the gravitational force is attractive only

- The electric force is much stronger than the gravitational force, due to the much larger value of the Coulomb's constant k compared to the gravitational constant G

4 0
4 years ago
List the 5 theoretical perspectives that underlie much of the research on human development. Also, name an individual strongly a
Mariana [72]

Answer:

25

Explanation:

5 theroical name indvivdual perspective asssssoitive each persp

5 0
3 years ago
Which of the following equations illustrates the law of conservation of<br> matter?
vagabundo [1.1K]

Answer:

I see no eaquations?

It should be matter=constant

3 0
3 years ago
In situation A, a bar magnet moves toward a stationary coil at a constant speed, and the maximum current is recorded. If the mag
slava [35]

The reversing of the magnet polarity will explain the different current reading.

Answer: Option D

<u>Explanation:</u>

According to Faraday's law of inductance, whenever a bar magnet is moved toward a stationary coil at constant speed, current will be generated in that coil. So in this case, the first maximum current in the above situation say A is recorded successfully.

Similarly, when the arrangement is kept as it is, in situation B, the current is observed to have different reading. This may be because of the polarity of the magnet would have changed leading to different current reading.

3 0
3 years ago
A mass of 0.560 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic mo
Slav-nsk [51]

Answer:

(a) A = 0.700m

(b) k = 80.6N/m

(c) x = -0.699m

(d) x = -0.350m

(e) t = 0.168s

Explanation:

Given the equation of motion for the spring

X = 0.700cos(12.0t), m = 0.56kg

(a) A = amplitude = 0.700m

(b) The angular velocity ω = 12rad/s

ω = √(k/m)

ω² = k/m

k = m×ω² = 0.56×12² = 80.6N/m

Spring constant k = 80.6N/m

(c) T = 2π/ω = 2π/12

T = 0.524s

At t = T/2 = 0.524/2 = 0.262s

So x = 0.700cos(12×0.262) = –0.699m

(d) At t = 2/3×T = 2×0.524/3 = 0. 349s

x = 0.700cos(12×0.349) = –0.350m

(e) to find t at x = -0.300m

–0.300 = 0.700cos(12t)

–0.300/0.700 = cos(12t)

cos(12t) = –0.429

12t = cos-¹(-0.429)

12t = 2.01

t = 2.01/12

t = 0.168s

8 0
4 years ago
Read 2 more answers
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