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Troyanec [42]
2 years ago
6

What is specific gravity​

Physics
1 answer:
Mrac [35]2 years ago
7 0

Answer:

It is the ratio of the density of a substance to the density of a given reference material.

Explanation:

<em>Specific gravity is also known as relative density.</em>

<u>To find the relative density of substance, you:</u>

  • Divide the density of substance measured
  • And divide that by the density of the reference

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For adults age 19–50, Dietary Guidelines recommend consuming at least _______ of vegetables and fruits daily. A. 3 cups B. 1 to
Sauron [17]
<span>For adults age 19–50, Dietary Guidelines recommend consuming at least 4 cups of vegetables and fruits daily. this means the answer is C</span>
4 0
3 years ago
Read 2 more answers
A rabbit runs 4.4 m across a lawn, stops, then runs 2.2 m back in the opposite direction. What is the rabbit’s displacement from
Alla [95]

Answer:

it is 2.2 m

Explanation:

because he goes back 2.2 m so 4.4 minus 2.2 equals 2.2

6 0
3 years ago
An object islaunched at velocity of 20 m/s in a direction making an angle of 25 degree upward with the horizontal. what is the m
Aneli [31]

Answer:

\displaystyle y_m=3.65m

Explanation:

<u>Motion in The Plane</u>

When an object is launched in free air with some angle respect to the horizontal, it describes a known parabolic path, comes to a maximum height and finally drops back to the ground level at a certain distance from the launching place.

The movement is split into two components: the horizontal component with constant speed and the vertical component with variable speed, modified by the acceleration of gravity. If we are given the values of v_o and \theta\\ as the initial speed and angle, then we have

\displaystyle v_x=v_o\ cos\theta

\displaystyle v_y=v_o\ sin\theta-gt

\displaystyle x=v_o\ cos\theta\ t

\displaystyle y=v_o\ sin\theta\ t -\frac{gt^2}{2}

If we want to know the maximum height reached by the object, we find the value of t when v_y becomes zero, because the object stops going up and starts going down

\displaystyle v_y=o\Rightarrow v_o\ sin\theta =gt

Solving for t

\displaystyle t=\frac{v_o\ sin\theta }{g}

Then we replace that value into y, to find the maximum height

\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2

Operating and simplifying

\displaystyle y_m=\frac{v_o^2\ sin^2\theta }{2g}

We have

\displaystyle v_o=20\ m/s,\ \theta=25^o

The maximum height is

\displaystyle y_m=\frac{(20)^2(sin25^o)^2}{2(9.8)}=\frac{71.44}{19.6}

\displaystyle y_m=3.65m

7 0
3 years ago
An 8.5-l tire is filled with 0.55 mol of gas at a temperature of 305 k. what is the pressure of the gas in the tire?
const2013 [10]

Answer:

1.62 atm

Explanation:

We can solve the problem by using the ideal gas equation:

pV=nRT

where:

p = ? is the pressure of the gas in the tire

V = 8.5 L is the volume of the tire

n = 0.55 mol is the number of moles of the gas

R = 0.0821 atm L / K mol is the gas constant

T = 305 K is the temperature of the gas

By re-arranging the equation and substituting the numbers in, we find:

p=\frac{nRT}{V}=\frac{(0.55 mol)(0.0821 Latm/Kmol)(305 K)}{8.5 L}=1.62 atm

8 0
4 years ago
Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 248 Hz, while the other produces 288 Hz.
zaharov [31]

Answer:

F = 268 Hz

Explanation:

The beat frequency is given as:

Beat Frequency = |Frequency 1 - Frequency 2|\\|

So, for the first flute and tuning fork:

20 Hz = |248 Hz - F|

where,

F = Frequency of tuning fork

F = 248 Hz ± 20 Hz

F = 268 Hz (OR) 228 Hz

Now, for the second flute and tuning fork:

20 Hz = |288 Hz - F|

where,

F = Frequency of tuning fork

F = 288 Hz ± 20 Hz

F = 268 Hz (OR) 308 Hz

Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.

<u>F = 268 Hz</u>

3 0
3 years ago
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