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OLEGan [10]
3 years ago
12

•1 if a saturn v rocket with an apollo spacecraft attached had a combined mass of 2.9 × 105 kg and reached a speed of 11.2 km/s,

how much kinetic energy would it then have?
Physics
1 answer:
Delicious77 [7]3 years ago
5 0
Kinetic energy = 1/2 (mass) (speed)²

Kinetic energy = (1/2) (2.9 x 10⁵ kg) (1.12 x 10⁴ m/s)²

= (0.5 x 2.9 x (1.12)² x 10¹³) kg-m²/s²

=  1.82 x 10¹³ Joules

atsanawfullotta joules !
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In a given circuit, the supplied voltage is 1.5 volts. One resistor is 3 ohms and the other is 2 ohms. Use Ohm's law to determin
ozzi

You haven't said whether the two resistors are connected
in series or in parallel.  It makes a difference.

--  If they are in series, then their combined effective resistance is

                 (3 + 2) = 5 ohms.

Current in the circuit is    (voltage)/(resistance) = 1.5/5 = 0.3 Amp.


--  If they are in parallel, then their combined effective resistance is

               (3 x 2) / (3 + 2) = (6/5) = 1.2 ohms.

Current in the circuit is  (voltage)/(resistance) =  1.5/1.2 = 1.25 Amp.
 
5 0
3 years ago
Read 2 more answers
A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine s
Tcecarenko [31]

Answer:

11.714 kW

Explanation:

Here is the complete question

A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest and is pulled up a mine shaft by a cable connected to a winch. The shaft is inclined at 34.0∘ above the horizontal. The car accelerates uniformly to a speed of 2.25 m/s in 10.5 s and then continues at constant speed. What power must the winch motor provide when the car is moving at constant speed?

Solution

Since the loaded ore car moves along the mine shaft at an angle of θ = 34° to the horizontal, if F is the force exerted on the cable, then the net force on the laoded ore car is F - mgsinθ = ma where  mgsinθ = component of the car's weight along the incline, m = mass of loaded ore car = 950 kg and a = acceleration

F = m(a + gsinθ)  

When the car is moving at constant speed, a = 0

So F = m(a + gsinθ) = F = 950(0 + 9.8sin34) = 5206.1 N

Since it continues at a constant speed of v = 2.25 m/s, the power of the winch motor is P = Fv = 5206.1 N × 2.25 m/s = 11713.7 W = 11.714 kW

5 0
3 years ago
g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?
beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{5.69^2 + 8^2}

F = \sqrt{32.3761 + 64}

F = \sqrt{96.3761}

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

4 0
3 years ago
Read 2 more answers
16 to 19 year old male and females are how much more likely to be involved in a crash?
Sedbober [7]
I say around 40% - 60%

https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp

(I just corrected the question. Sorry if it is still incorrect.)
6 0
3 years ago
The sensitivity of a measuring instrument is the value of the smallest quantity that can be read or estimated with it. What is t
nirvana33 [79]

Answer:

The smallest part of a millimeter that can be read with a digital caliper with a four digit display is 0.02mm. Thus, it has to be converted to centimetre. So, divide by 10, we then have 0.02/10= *0.002cm* not mm.

6 0
3 years ago
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