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OLEGan [10]
3 years ago
12

•1 if a saturn v rocket with an apollo spacecraft attached had a combined mass of 2.9 × 105 kg and reached a speed of 11.2 km/s,

how much kinetic energy would it then have?
Physics
1 answer:
Delicious77 [7]3 years ago
5 0
Kinetic energy = 1/2 (mass) (speed)²

Kinetic energy = (1/2) (2.9 x 10⁵ kg) (1.12 x 10⁴ m/s)²

= (0.5 x 2.9 x (1.12)² x 10¹³) kg-m²/s²

=  1.82 x 10¹³ Joules

atsanawfullotta joules !
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Determine the linear velocity of an object with an angular velocity of 5.9 radians per second at a distance of 12 centimeters fr
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3 years ago
An electron moving in a direction perpendicular to a uniform magnetic field at a speed of 1.6 107 m/s undergoes an acceleration
umka2103 [35]

Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

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F=qvB     (1)

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v: speed of the electron = 1.6*10^7 m/s

B: magnitude of the magnetic field = ?

By the Newton second law you also have that the magnetic force is equal to:

F=qvB=ma       (2)

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a: acceleration of the electron = 7.0*10^16 m/s^2

You solve for B from the equation (2):

B=\frac{ma}{qv}\\\\B=\frac{(9.1*10^{-31}kg)(7.0*10^{16}m/s^2)}{(1.6*10^{-19}C)(1.6*10^7m/s)}\\\\B=0.024T

The direction of the magnetic field is found by using the right hand rule.

The electron moves upward (+^j). To obtain a magnetic forces points to the positive x-direction (+^i), the direction of the magnetic field has to be to the positive z-direction (^k). In fact, you have:

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Where the minus sign of the ^j is because of the negative charge of the electron.

Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

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