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2 years ago

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Rhea is a high school gymnast, and she is really inspired by Simone Biles. Rhea really admires her skill and dedication. However

, her friend tells her that she should pick a more realistic role model since Simone Biles is an exceptional athlete and few gymnasts in the world will ever be that good. What is the BEST advice for Rhea?
A.
Rhea should listen to her friend and find someone more ordinary.
B.
Biles is very famous and Rhea probably will not be, so it is unrealistic to admire her.
C.
Only people that are at the absolute top of their field should be considered role models.
D.
If Rhea is inspired and not too focused on comparing abilities, Biles is a good role model.

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1 answer:

Alborosie2 years ago

6 0

Answer: D

Explanation:

If Rhea is inspired and not too focused on comparing abilities, Biles is a good role model.

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A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a

soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g= $\frac{46}{1000} kg=0.046 kg$

$1kg=1000 g$

Constant force=F=25.6 N/m

Initial displacement= $A_1=0.296 m$

Final displacement= $A_2=0.12 m$

Time=t=4.55 s

Damping force= $F_x=-bv_x$

We have to find the magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

$x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)$

For maximum displacement $cos(w't+\phi)=1$

Therefore , $x=A_2$

Substitute the values

$A_2=A_1e^{-\frac{-b}{2m}t}$

$e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}$

$-\frac{b}{2m}t=ln\frac{A_2}{A_1}$

$lnx=y\implies x=e^y$

Substitute the values

$-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}$

$\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}$

$\frac{2\times 0.046}{4.55}=0.9b$

$b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s$

Hence,the magnitude of damping constant b=0.022kg/s

3 0

2 years ago

A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a sp

dusya [7]

from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A) What is its speed after falling for 2.00s?

from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

from the equation of motion $s=ut+0.5at^{2}$ we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

$v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}$

v = 15.4 m/s

7 0

2 years ago

If two persons do the same amount of work , they may have different power ? why ?

iris [78.8K]

Hey there mate :)

Even if two persons are given the same work load, the speed of the work done gets different by the energy of those persons.

No one is sure that he/she can complete the work within the time. He may or may not.

Also, the physical characteristics makes the work different. If one person has so much power to work all day, the other person may not have.

Therefore, <em>even if two persons do the same amount of work , they may have different power</em><em>.</em>

4 0

2 years ago

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two

Pepsi [2]

Answer:197.504 N

Explanation:

Given

Two Charges with magnitude Q experience a force of 12.344 N

at distance r

and we know Electrostatic force is given

$F=\frac{kq_1q_2}{r^2}$

$F=\frac{kQ\cdot Q}{r^2}$

$F=\frac{kQ^2}{r^2}$

Now the magnitude of charge is 2Q and is at a distance of $\frac{r}{2}$

$F'=\frac{k2Q\cdot 2Q}{\frac{r^2}{2^2}}$

F'=16F

F'=197.504 N

4 0

2 years ago

The following letter are used to help remember the characteristics of minerals:S I C C N. What does the S stand for?

Dennis_Churaev [7]

Your answer would be A. Solid. Hope this helps!

7 0

2 years ago