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2 years ago

12

I watch television from 5 o clock until half past. How long do I watch for?I watch television from 5 o clock until half past. Ho

w long do I watch for?

1 answer:

Blababa [14]2 years ago

8 0

Answer:

30 minutes

Step-by-step explanation:

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The combined height of one fir tree and one pine tree is 212121 meters. The height of 444 fir trees stacked on top of each other

Drupady [299]

Answer:

Height of fir tree = 9 meters

height of pine tree= 12 meters

Step-by-step explanation:

The combined height of one fir tree and one pine tree is 21 meters. The height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Let x be the height of fir tree and y be the height of pine tree

$x+y=21$

Subtract x from both sides

$y=21-x$

height of 4 fir trees = pine tree +24

$4x=y+24$

Substitute 21-x or y in the above equation

$4x=21-x+24$

Add x on both sides

$5x=45$

Divide by 5 on both sides

x=9

Now plug in 9 for x and find out y

$y=21-x$

$y=21-9$

y=12

Height of fir tree = 9 meters

height of pine tree= 12 meters

4 0

4 years ago

Simplify 2(x-4)+7(x+4)

Irina-Kira [14]

It would 9x+20 because u have to distribute

5 0

3 years ago

What is the surface area of the solid that this net can form?

Ivanshal [37]

Option B:

Surface area of the solid is 730 square millimeters.

Solution:

Area of the rectangle = length × breadth

Length of the top net = (25 + 8 + 8) mm = 41 mm

Breadth of the top net = 5 mm

Area of the Top net = 41 mm × 5 mm

= 205 square mm

Area of the second net = 25 mm × 8 mm

= 200 square mm

Area of the third net = 25 mm × 5 mm

= 125 square mm

Area of the bottom net = 25 mm × 8 mm

= 200 square mm

Surface area of the solid = 205 mm + 200 mm + 125 mm + 200 mm

= 730 square mm

Hence surface area of the solid is 730 square millimeters.

Option A is the correct answer.

6 0

4 years ago

Read 2 more answers

Calculate the limit of the function with L'Hospital rule

mr_godi [17]

Answer:

L=24

Step-by-step explanation:

L'Hopital's Rule for Evaluating Limits:

Rule is that if $\lim_{x \to a} \frac{f(x)}{g(x)}$ takes $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form, then,

$\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}$

where $f'(x)=\frac{df(x)}{dx}$ and $g'(x)=\frac{dg(x)}{dx}$

Now coming to the problem,

$L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}$

Here $f(x)=cot^{3}x-3cotx$ and $g(x)=cos(x+\frac{\pi}{3} )$

Substituting $x=\frac{\pi}{6}$ in f(x) and g(x),

$f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0$

$g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0$

Since L takes the form $\frac{0}{0}$ , using l'hopital's rule

$L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}$

now substituting $x=\frac{\pi}{6}$ ,

$L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24$

6 0

3 years ago

I need help with this asap please

Lorico [155]

Answer:

The perimeter is 100 feet. This means that all the sides of the shape must add up to equal 100.

x + x + 5 + x - 3 + x + 4 = 100

4x + 5 - 3 + 4 = 100

4x + 6 = 100

4x = 94

x = 94/4

x = 23.5 feet

3 0

3 years ago