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MrRa [10]
3 years ago
7

Most transition metal ions contain partially occupied ________ subshells.

Chemistry
1 answer:
Vitek1552 [10]3 years ago
6 0
They contain d subshells
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Summarize the process a scientist goes through to come up with a<br> satisfactory solution.
maria [59]
Guess and check, test, trial and error, completion.
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3 years ago
A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M
Archy [21]

Answer:

Ksp=2.0x10^{-14}

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)

The solubility product can be set up as follows:

Ksp=[Cd^{2+}][OH^-]^2

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}

Regards!

3 0
3 years ago
The scientific method is one application of critical thinking.true or false
kumpel [21]
The best answer between the two choices would be the first option TRUE because the scientific method is used to do more advance research and investigation on things.
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If 156 grams of chromium react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of chr
Sunny_sXe [5.5K]

Answer:

=759.95 grams.

Explanation:

The molar mass of chromium is 51.9961 g/mol

Therefore the number of moles of chromium in 156 grams is:

Number of moles =mass/RAM

=156g/51.9961g/mol

=3 moles.

From the equation provided, 3 moles of chromium metal produce 2 moles of Chromium oxide.

Therefore 3 moles of chromium produce:

(3×2)/4 moles =1.5 moles of chromium oxide.

I mole of chromium oxide has a mass of 151.99 g

Thus 1.5 moles= 1.5mole ×151.99 g/mol

=759.95 grams.

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Elements in Group 4A
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Answer:

helium hydrogen

Explanation:

lithium beryllium bottom carbon

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