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1 year ago

Calculate the percent covalent character of a chemical bond between iodine and lithium.

Chemistry

1 answer:

raketka [301]1 year ago

3 0

Answer:

27966692

Explanation:

I don't know if this is right or not

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The volume of a given mass of agas is 360cm cubic at 50 degrees and 700 milimetres Hg .find it's volume at s.t.p

saveliy_v [14]

Answer:

V₂ =279.9 cm³

Explanation:

Given data:

Initial volume = 360 cm³

Initial temperature = 50°C

Initial pressure = 700 mmHg

Final volume = ?

Final temperature = 273 k

Final pressure = 1 atm

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Solution:

We will convert the mmHg to atm.

700/760 = 0.92 atm

and °C to kelvin.

50+273 = 323 K

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 0.92 atm × 360 cm³ × 273 K / 323 K ×1 atm

V₂ = 290417.6 atm .cm³. K / 323 k. atm

V₂ =279.9 cm³

8 0

3 years ago

The mass of an atom may be found by adding the

Darina [25.2K]

Answer:

protons and neutrons

Explanation:

5 0

2 years ago

A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are

ohaa [14]

Answer: The final volume of the oxygen gas is 4.04 L

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K$

Putting values in above equation, we get:

$\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L$

Hence, the final volume of the oxygen gas is 4.04 L

8 0

3 years ago

Why is water important?

expeople1 [14]

Answer:

Its a natural resource used around the world

4 0

2 years ago

what is the specific latent heat of fusion for a substance that takes 550 kj to melt 14 kg at 262 k? brainly answers

Ket [755]

q = mL

L = q/m = 550 kJ/14 kg = 39 kJ/kg

3 0

2 years ago