Calculate the percent covalent character of a chemical bond between iodine and lithium.

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

aleksandr82 [10.1K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 13.83 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.300 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.300M=\frac{\text{Moles of NaI}}{0.200L}\\\\\text{Moles of NaI}=(0.300mol/L\times 0.200L)=0.06mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.06 moles of NaI will produce = $\frac{1}{2}\times 0.06=0.03mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.03 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.03mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.03mol\times 461.1g/mol)=13.83g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 13.83 grams

6 0

3 years ago

E. Give evidence to support or dispute: "In nature, the chance of finding one isotope

Nadusha1986 [10]

Answer:

This question appears incomplete

Explanation:

However, the chance of finding one isotope of an element is not the same for all elements because some elements/isotopes are more in abundance than some other elements/isotopes; for example the most abundant element on earth is nitrogen-14, hence the chances of finding nitrogen-14 in nature is higher the chances of finding any isotope of Xenon.

Also, while isotopes occur naturally, some do not. Hence, the chances of finding a naturally occurring isotopes (no matter how rare like Xenon-126) is higher than the chances of finding artificial radioisotopes like technetium-95 and promethium-146 (whose chances are zero because they cannot be found naturally occurring).

3 0

3 years ago

How many moles are equal to 83.4 L of O2?

ladessa [460]

Answer:

$3.72mol$

Explanation:

Hello,

In this case, we consider that at STP conditions (273 K and 1 atm) we know that the volume of 1 mole of a gas is 22.4 L, thereby, for 83.4 L, the resulting moles are:

$22.4L\rightarrow 1mol\\83.4L\rightarrow X\\X=\frac{83.4L*1mol}{22.4L}=3.72mol$

This is a case in which we apply the Avogadro's law which relates the volume and the moles as a directly proportional relationship.

Best regards.

8 0

3 years ago

Which of the following measurements has FOUR significant figures?

garik1379 [7]

Answer:

A) 0.1005 m

sorry if it's wrong

7 0

3 years ago

What kind of chemical bonds are represented by the product in the following diagram?

katovenus [111]

The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.

4 0

3 years ago