Molar solubility of AgCl will be 0.59 × M.
The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.
A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.
Calculation of molar solubility:
Given data:
M = 0.30 M
= 1.77 ×
The reaction can be written as:
AgCl ⇔
s s (s+0.30)
= [ ]+ []
1.77 × = s (0.30)
s = 1.77 × / 0.3
s = 0.59 × M
Therefore, molar solubility of AgCl will be 0.59 × M.
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Answer:
In Cl, the 2 is a subscript because it indicates there are 2 of the same elements. The Lewis structure would display it as Cl-Cl.
On the other hand, a superscript would indicate a specific charge.
All subscripts show the amount of the specific element there is.
An example would be O or N, they both show that there are 2 of the same elements.
If the subscript is outside a parenthesis such as it indicates there are 2 molecules.
Answer:
chemical reactions are: the combination of elements to form compounds, the ... Equations may be expressed in words: Mercury(II) oxide decomposes to mercury and oxygen. ... The arrow ( ) means "reacts to form" or "yields.
Explanation: