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vova2212 [387]
3 years ago
6

Which of the following most likely happens when the number of particles of a gas decreases?

Chemistry
1 answer:
Papessa [141]3 years ago
3 0

Answer: C. The number of collisions of gas particles decreases

Explanation: As temperature decreases so does everything else same with increase.

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I need some help with a long chemistry problem. Anything is appreciated!
Mkey [24]

Answer:

The CSI is wrong.  

Explanation:

1. Find the volume of the pool

The formula for the volume of a cylinder is  V = πr²h .

D = 12 m; h = 10 m

r = D/2 = (12 m/2) = 6.0 m

V = πr²h = π × (6.0 m)² × 10 m = π × 36 m²× 10 m = 360π m³ = 1100 m³

= 1.1. × 10⁶ L

2. Calculate the moles of OH⁻

n = cV = 1.0 × 10⁻² mol·L⁻¹ × 1.3 × 10⁶ L = 11 000 mol of OH⁻                                                                                                                                                                                                                                                                                                                              

3. Calculate the moles of acetic acid needed for neutralization

HA + OH⁻ ⟶ A⁻ + H₂O

The molar ratio of is 1 mol HA:1 mol OH⁻, so you need 11 000 moL of acetic acid.

4. Calculate the actual moles of acetic acid

You have four 5 L jugs of acetic acid pH 2 .

Volume = 20 L

[H⁺] = 10⁻² mol·L⁻¹ = 0.01 mol·L⁻¹

(a) Set up an ICE table

                      HA + H₂O ⇌ A⁻  + H₃O⁺

I/mol·L⁻¹:          c                   0         0

I/mol·L⁻¹:     - 0.01             +0.01    +0.01

I/mol·L⁻¹:    c - 0.01             0.01     0.01

K_{\text{a}} = \dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}  = 1.76 \times 10^{-5}

(b) Calculate the concentration of acetic acid

\begin{array}{rcl}\dfrac{\text{[A]}^{-}\text{[H$_{3}$O$^{+}$]}}{\text{[HA]}}& = & 1.76 \times 10^{-5}\\\\\dfrac{0.01\times 0.01}{c}& = & 1.76 \times 10^{-5}\\\\1 \times 10^{-4} & = & 1.76 \times 10^{-5}c\\c & = & \dfrac{1 \times 10^{-4}}{1.76 \times 10^{-5}}\\\\ & = & \text{6 mol/L}\\\end{array}

The concentration of the acetic acid is 6 mol·L⁻¹

(c) Calculate the moles of acetic acid

n = \text{20 L} \times \dfrac{\text{6 mol}}{\text{1 L}} = \textbf{100 mol}

You have 100 mol of acetic acid.

The CSI is wrong.

You don't have enough acetic acid to neutralize the pool.

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Which of the following experiments would be considered unethical?
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Answer:

The answer is C)

Explanation:

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Sometimes, based on the electron configurations of the elements involved, a possible chemical formula for a compound can be pred
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Answer:

D)the first ionization energy (IE1) of B is most probably lower than the first ionization energy (IE1) of A

Explanation:

As mentioned the possible chemical formula for a compound can be predicted from electron configurations of the elements.

The first element 'A' has electronic configuration as "[core]ns²

It means it has two valence electrons and it can give those valence electrons to attain noble gas or full filled stability.

So the element is most likely to form a dipositive ion.

Now for element B the configuration is :[Core]ns²np⁵

thus it has seven valence electrons and it will most likely to accept an electron to gain full filled stability. So B will form a mono negative ion.

The possible formula will be AB₂ [Like MgCl₂]

So the false statements are:

D)the first ionization energy (IE1) of B is most probably lower than the first ionization energy (IE1) of A : the first ionization energy of A will be lower than B as B cannot give an electron easily.

The other statements are correct:

A) element A serves as the reducing agent in the reaction to form AxBy : As A will lose electrons so it will acts as reducing agent and itself gets oxidized

B) yes it is whole number as calculated above.

C) x + y = 1+2 = 3

E) Already calculated that B has oxidation state of -1.

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3 years ago
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