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2 years ago

Can the work output of an engine be greater than the source of energy.

Chemistry

1 answer:

Arlecino [84]2 years ago

3 0

Answer:

Explanation:

the output can never be greater than the input

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Or a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy?

ELEN [110]

This electronic transition would result in the emission of a photon with the highest energy: 4p – 2s This can be the same with the emission of 4f to 2s which would emit energy in the visible region. The energy in the visible region would emit more energy than in the infrared region which makes this emission to have the highest energy.

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3 years ago

A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern

Arada [10]

Answer: The volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

Explanation:

To calculate the volume of water, we use the equation given by ideal gas, which is:

$PV=nRT$

or,

$PV=\frac{m}{M}RT$

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of container = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L$

Converting this value into $m^3$ , we use the conversion factor:

$1m^3=1000L$

So, $\Rightarrow (\frac{1m^3}{1000L})\times 154.21L$

$\Rightarrow 0.1542m^3$

To calculate the internal energy, we use the equation:

$U=\frac{3}{2}nRT$

or,

$U=\frac{3}{2}\frac{m}{M}RT$

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.314J/K.mol$

T = temperature = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

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3 years ago

A student, wearing chemical safety goggles and a lab apron, is to perform a laboratory test to determine the pH value of two dif

Setler79 [48]

They should probably wear gloves. A pH of 2.0 is a very strong acid, and it can easily irritate their hands. They should also remember to NEVER touch their face, mouth, etc. and to keep all chemicals on the laboratory table.

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3 years ago

What precautions must be taken when you introduce a mixture of compounds to be separated onto a liquid chromatography column?

earnstyle [38]

The slim exit of the column is first persisted with glass wool or a permeable plate in order to sustain the column packing element and keep it from getting out of the tube. Then the adsorbent solid, which is usually a silica, is firmly packed into the glass tube to make the separating column. The packing of the non-moving phase into the glass column must be done with precaution to create an even distribution of material. An even distribution of adsorbent material is very important to lessen the existence of air bubbles and/or channels inside the column. To finish preparing the column, the solvent to be used as the mobile phase is delivered through the dry column. Then the column is said to be "wetted" and the column must stay wet throughout the entire procedure. Once the column is properly prepared, the sample to be separated is placed at the top of the wet column.

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3 years ago

If 150 g dimethylhydrazine reacts with excess dinitrogen tetroxide and the product gases are collected at 127oC in an evacuated

zhuklara [117]

Answer : The the partial pressure of the nitrogen gas is 0.981 atm.

The total pressure in the tank is 2.94 atm.

Explanation :

The balanced chemical reaction will be:

$(CH_3)_2N_2H_2(l)+2N_4O_4(l)\rightarrow 3N_2(g)+4H_2O(g)+2CO_2(g)$