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allsm [11]
2 years ago
14

Estimate 22,752 divdided by 18 , I'm doing a lot tonight, have 10 assesments due tom

Mathematics
1 answer:
mestny [16]2 years ago
5 0

Answer:

1264

Step-by-step explanation:

is the answer...........

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Answer: 8

Step-by-step explanation:

7 0
2 years ago
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4 0
2 years ago
What is the midpoint of (-23,-14) and (-18,2)
zloy xaker [14]

Given two coordinates point 1 as (-23,-14) and point 2 as(-18,2).

To find the midpoint we would use the formula below;

\text{midpoint(x,y)}=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Where x1=-23, x2=-18, y1=-14, y2=2

We would substitute the values into the midpoint formula.

\begin{gathered} \text{midpoint =(}\frac{-23-18}{2},\frac{-14+2}{2}) \\ =(-\frac{41}{2},-6) \end{gathered}

Therefore, the answer is

\text{midpoint}=(-\frac{41}{2},-6)

7 0
1 year ago
A game decreased in price by 1/5. After the reduction it was priced at £48. What was the original price of the game?
Agata [3.3K]

Answer:

1/5 is equal to 20% so you multiply 48 by .20 and you get 9.6 and your take 9.6 and add it to 48. your answer will be 57.6

3 0
3 years ago
Read 2 more answers
If you roll a number cube two times, what is the probability of rolling an even on the first roll and a four on the second roll?
Bad White [126]

Answer:

1/12

Step-by-step explanation:

Probability is a ratio derived as the number of possible outcomes divided by the total outcome.

On a number cube, the even sides are 2, 4 and 6. This means that the possible outcome for rolling an even is 3 while the total outcome is 6. Hence the probability of rolling an even P(E)

= 3/6

The probability of rolling a 4  P(4)

= 1/6 (4 appears on one side)

Hence  the probability of rolling an even on the first roll and a four on the second roll

P(En4) = 3/6 * 1/6

= 3/36

= 1/12

7 0
2 years ago
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