Answer:
0.74 moles of oxygen are required for combustion
Explanation:
Given data:
Number of moles of oxygen required = ?
Mass of Mg = 35.5 g
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 35.5 g/ 24 g/mol
Number of moles = 1.48 mol
Now we will compare the moles of Mg with oxygen.
Mg : O₂
2 : 1
1.48 : 1/2×1.48 = 0.74 mol
0.74 moles of oxygen are required for combustion.
Answer:
are you talking about plant cells?
Explanation:
Metalloid
Explanation:
If an element is lustrous, brittle and a semi-conductor, it is best classified as a metalloid.
Metalloids shares attributes of metals and non-metals.
- They are often described as semi-metals as they do not share the full properties that makes a metal a metal.
- Metalloids are lustrous but not malleable like metals.
- They do not conduct electricity but they do so on certain conditions.
- Examples are silicon, germanium, boron, arsenic e.t.c
- They are usually found in the middle of the periodic table.
- They are not readily alloyed with metals.
Learn more:
Metalloid brainly.com/question/3023499
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The heart is classified as an organ.
Answer:
The noble gas notation for sodium is [Ne]
Explanation: