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3 years ago

8

are you alive...................................................................................................................

................................

2 answers:

lesya [120]3 years ago

7 0

Answer:

i have a magic trick

Explanation:

go here to see it brainly.com/question/25776258

scoundrel [369]3 years ago

4 0

Answer:

yes y?

Explanation:

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Which substance is the reducing agent in this reaction? 16h++2cr2o72−+c2h5oh→4cr3++11h2o+2co2 express your answer as a chemical

lana66690 [7]

16 H + + 2Cr2O72- + C2H5OH → 4 Cr3 + +11H2O +2CO2

The reducing agent is C2H5OH

Explanation

reducing agent is a substance that loses or donate electrons in a chemical reaction. C2H5OH is the one which donate electrons in the above chemical equation.

7 0

3 years ago

Can someone please helpppp!

dolphi86 [110]

Answer: A

Aloha is the one that loses a helium

5 0

3 years ago

What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l

Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law: $PV=nRT$ where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units: $R=0.0821\frac{L\cdot atm}{mol\cdot K}$

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means $T=273.15K$ and $P=1atm$

Lastly, we must calculate the number of moles of $O_2(g)$ there are. Given 0.80g of $O_2(g)$ , we will need to convert with the molar mass of $O_2(g)$ . Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2: $32g\text{ }O_2=1mol\text{ }O_2$

Thus, $\frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n$

Isolating V in the Ideal Gas Law:

$PV=nRT$

$V=\frac{nRT}{P}$

...substituting the known values, and simplifying...

$V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}$

$V=0.56L \text{ } O_2$

So, 0.80g of $O_2(g)$ would occupy 0.56L at STP.

5 0

2 years ago

Read 2 more answers

The addition of phosphate to a chemical compound is called A. glycolysis. B. oxidation. C. reduction. D. phosphorylation.

stich3 [128]

Answer:

Option (D)

Explanation:

Phosphorylation can be simply defined as the addition of a phosphate group to an organic and inorganic molecule. This process helps in regulating the processes that occur in the cells. It leads to the growth and development of cells and this process is efficiently carried out with the help of enzymes like kinase. It also plays an important role in transferring the signals within the cells, synthesis, and functioning of proteins within the cells, and storing as well as releasing of energy.

Thus, the correct answer is option (D).

5 0

3 years ago

If Magnesium Sulfide reacts with oxygen in the air, what will be produced?

sweet [91]

IF magnesium sulfide reacts with oxygen in the air it will produce

magnesium oxide + sulfur (IV) oxide

<u><em>explanation</em></u>

magnesium sulfide burn in oxygen to produce magnesium oxide and sulfur (iv) oxide according to the equation below

2MgS +3O2 →2MgO +2SO2

that is 2 moles of MgS react with 3 moles of O2 to produce 2 moles of MgO and 2 moles of SO2

6 0

3 years ago