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julia-pushkina [17]
3 years ago
6

A student wants to collect data during an experiment about the transfer of kinetic energy in a sample of water and ice. Which to

ol will help her collect the necessary data?
Chemistry
1 answer:
erastova [34]3 years ago
3 0

Given what we know, the tool in question that will help the student collect data regarding the transfer of kinetic energy between water and ice would be a thermometer.

<h3>How does the thermometer measure kinetic energy?</h3>

It does not do so directly. However, kinetic energy in water molecules is reflected in the temperature of the water. When water molecules increase their kinetic energy and move more, they become hotter. Increased or decreased heat is an indirect way to measure the transfer of kinetic energy in water.

Therefore, given that the temperature of the water is a reflection of the transfer of kinetic energy happening, we can confirm that the tool that will help the student collect the data needed is a thermometer.

To learn more about kinetic energy visit:

brainly.com/question/999862?referrer=searchResults

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What is the molarity of HCl found in a titration where 50 ml of HCl is titrated with 50 ml of .1 M NaOH? Needs to be answered as
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0.1 mol/L . The concentration of the HCl is 0.1 mol/L

a) Write the <em>balanced chemical equation </em>

HCl + NaOH → NaCl + H2O

b) Calculate the <em>moles of NaOH </em>

Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)

= 0.0050 mol NaOH

c) Calculate the <em>moles of HCl </em>

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A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the
IgorC [24]

Answer: The empirical formula for the given compound is Cr_2S_3

Explanation : Given,

Mass of product = 0.963 g

Mass of Cr = 0.500 g

Mass of S = 0.963 g  - 0.500 g = 0.463 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Cr =\frac{\text{Given mass of Cr}}{\text{Molar mass of Cr}}=\frac{0.500g}{52g/mole}=0.00962moles

Moles of S = \frac{\text{Given mass of S}}{\text{Molar mass of S}}=\frac{0.463g}{32g/mole}=0.0145moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00962 moles.

For Cr = \frac{0.00962}{0.00962}=1

For S = \frac{0.0145}{0.00962}=1.5

To make in a whole number we are multiplying the ratio by 2, we get:

The ratio of Cr : S = 1 : 1.5

The ratio of Cr : S = 2 : 3

Step 3: Taking the mole ratio as their subscripts.

The ratio of Cr : S = 2 : 3

Hence, the empirical formula for the given compound is Cr_2S_3

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