Answer:
Law of Conservation of Energy
Explanation:
There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. The atomic radius in decreasing order is Bi>Sb>As>N>O.
<h3>
What is periodic table?</h3>
Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.
Along the period, the size of elements decreases. Down the group the size of elements increases. The atomic radius in decreasing order is Bi>Sb>As>N>O.
Therefore, atomic radius in decreasing order is Bi>Sb>As>N>O.
Learn more about periodic table, here:
brainly.com/question/11155928
#SPJ1
Answer : The value of
for the reaction is -959.1 kJ
Explanation :
The given balanced chemical reaction is,

First we have to calculate the enthalpy of reaction
.

![\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2O%29%7D%2Bn_%7BSO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28SO_2%29%7D%5D-%5Bn_%7BH_2S%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2S%29%7D%2Bn_%7BO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28O_2%29%7D%5D)
where,
= enthalpy of reaction = ?
n = number of moles
= standard enthalpy of formation
Now put all the given values in this expression, we get:
![\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5B2mole%5Ctimes%20%28-242kJ%2Fmol%29%2B2mole%5Ctimes%20%28-296.8kJ%2Fmol%29%7D%5D-%5B2mole%5Ctimes%20%28-21kJ%2Fmol%29%2B3mole%5Ctimes%20%280kJ%2Fmol%29%5D)

conversion used : (1 kJ = 1000 J)
Now we have to calculate the entropy of reaction
.

![\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28H_2O%29%7D%2Bn_%7BSO_2%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28SO_2%29%7D%5D-%5Bn_%7BH_2S%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28H_2S%29%7D%2Bn_%7BO_2%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28O_2%29%7D%5D)
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of formation
Now put all the given values in this expression, we get:
![\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5B2mole%5Ctimes%20%28189J%2FK.mol%29%2B2mole%5Ctimes%20%28248J%2FK.mol%29%7D%5D-%5B2mole%5Ctimes%20%28206J%2FK.mol%29%2B3mole%5Ctimes%20%28205J%2FK.mol%29%5D)

Now we have to calculate the Gibbs free energy of reaction
.
As we know that,

At room temperature, the temperature is 500 K.


Therefore, the value of
for the reaction is -959.1 kJ
Atomic number
Explanation:
The atomic number is enough clue that can be used to proper place elements without any other information. The atomic number is the number of protons in an atom. Protons are positively charged particles in the nucleus of an atom.
- To place elements on the periodic table, the periodic law which states that "properties of elements are a periodic function of their atomic number" must be obeyed.
- Using the atomic number, one can determine the number of electrons in a neutral atom, the charges on an ion e.t.c.
- Atomic number can also be used to write the electronic configuration of an atom be it the shell notation, sublevel notation and the lewis dot structure.
Learn more:
Atomic numbers brainly.com/question/5425825
About atomic numbers brainly.com/question/1379579
Electronic configuration brainly.com/question/549647
#learnwithBrainly
The correct options are as follows:
1. In the chemical equation given above, Fe3+ IS REDUCED.
A reduction is a process in which an atom of an element gains an electron and therefore become reduced. In this type of reaction, the positive character of the atom is reduced. Looking at the equation given above, you will notice that, the positive character of Iron is reduced form +3 to +2.
2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.
3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />