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mihalych1998 [28]
3 years ago
5

a 455n gymnast jumps upward a distance of 1.5 meters to reach the uneven parallel bars. how much work did she do before she even

began her routine
Physics
1 answer:
Taya2010 [7]3 years ago
3 0
Work = force x distance
Work = 455N (weight force) x 1.5m (distance)
Work done = 682.5J
Hope this helped!
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Answer:

563.86 N

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slava [35]

Answer:

The angular speed of the wheel is 0.452 rad/s

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Explanation:

<em>Hey</em><em>,</em><em> </em><em>there</em><em>!</em>

<em>Here</em><em>,</em><em> </em><em>In</em><em> </em><em>question</em><em> </em><em>given</em><em> </em><em>that</em><em>, </em>

<em>potential</em><em> </em><em>difference</em><em> </em><em>(</em><em>V</em><em>)</em><em>=</em><em> </em><em>8</em><em>V</em>

<em>resistance</em><em> </em><em>(</em><em>R</em><em>)</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ohm</em>

<em>Now</em><em>,</em>

<em>According</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Ohm's</em><em> </em><em>law</em><em>,</em>

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