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MaRussiya [10]
3 years ago
6

What is equal to the kinetic energy of a car with a mass of 0.5t (tonne) if it travels evenly at 70 km/h?

Physics
1 answer:
Aleonysh [2.5K]3 years ago
5 0
Formula for kinetic energy is 1/2mv^2 so that answer should most probably be 94521.6J
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What are newtons laws and their description
Aliun [14]

This may help

https://www.britannica.com/science/Newtons-laws-of-motion

But I don't know

4 0
3 years ago
When mapping the equipotentials on the plates with different electrode configurations you may find that some have significant ar
Olenka [21]

Answer:

v = 10 V and E = 2 10³ N/C

Explanation:

The electrical potentials and the electric field at one point are related by the expression

            ΔV = - ∫ E. dS

Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.

 If the potential difference is the most usual that is V = 10 V, the electric field is

   s = 0.5 cm = 0.5 10⁻² m

                E = ΔV / S

                E = 10/0.5 10⁻²

                 E = 2 10³ N / C

4 0
4 years ago
Create a list of at least five different shapes of signs. For each of the five items on your list, identify two specific signs.
Nitella [24]
Hey bud, Good to see you again!

Okay so lets get to work huh? :D

Circle - Railroad advance warnings, and some bus signs.
Octagon - Stop signs, and slow signs (for flooding on roads).
Triangle - People crossing, People working.
Square - parking, speed limit.
Diamond - Bicyclist, animal crossing.

Hope this helped. Have a great day!


5 0
4 years ago
Read 2 more answers
14. A ball initially at rest rolls without slipping
elena-s [515]

Answer:

v = √(10gh/7)

Explanation:

Initial gravitational energy = final rotational energy + kinetic energy

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For a solid sphere, I = ⅖ mr².

For rolling without slipping, ω = v/r.

mgh = ½ (⅖ mr²) (v/r)² + ½ mv²

mgh = ⅕ mv² + ½ mv²

mgh = 7/10 mv²

10/7 gh = v²

v = √(10gh/7)

7 0
3 years ago
How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​
umka21 [38]

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

7 0
3 years ago
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