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vladimir2022 [97]
3 years ago
14

What is the lowest temperature that a substance can reach

Physics
2 answers:
MAXImum [283]3 years ago
8 0
They can reach to absolutely zero.

hope that this helps
irina1246 [14]3 years ago
4 0
It's known as Absolute Zero. On the Kelvin scale, 0 is the lowest that anything can reach in temperature. It's supposedly impossible to reach, but it's the known limit.
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Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west en
Brut [27]

Answer:

The corridor's distance is "90 m".

Explanation:

  • She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
  • Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
  • Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
  • The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
  • Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒  2x + 2y = 60

⇒  x + y = 30

The total distance of the corridor will be:

=  x + 2x + 2y + y

=  3\times (x + y)

=  3\times 30

=  90 \ m

4 0
3 years ago
A school bus transporting students to school is an example of
Andru [333]
The last one, Kinetic energy bc it is taking them to school
4 0
3 years ago
Read 2 more answers
¿Por qué en algunas partes el agua tiene mayor presión?
Phantasy [73]
Cuando la presión aumenta en el agua, disminuye el punto de fusión del hielo. Ósea esta a temperatura muy alta.


Espero que esto te ayude y no me haya confundido
7 0
2 years ago
A person walks 24 meters at 3 m/s. How long did it take them
asambeis [7]

Hi my dear friend,

2m*30 = 60m

~Thank you

4 0
3 years ago
Read 2 more answers
Why do the graphs differ?​
melisa1 [442]

Well first graph represents rectangular hyperbola

vu = c^2 ( c is constant)

AS 1/v + 1/u = 1/f

Take1/ f to be constant c

1/v = c - 1/u

it is of the form y = - x + k

Slope = -1 having intercept k as shown in fig 2

3 0
3 years ago
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