Question

A copper sulphate solution contained 0.100 moles of copper sulphate dissolved in 0.500 dm cubed of water. Calculate the mass of copper sulphate in 30.0cm cubed of this solution. Relative formula mass (mr): CuSO4= 159.5

Answer 1

Answer:

cm^3 —> dm^3

divide by 1000

159.5 — Mr of CuSO4

n (moles in mol) = c (concentration in mol/dm^3) * v (volume in dm^3)

0.100 mol of CuSO4 dissolved in 0.5dm^3 of water

calculate for mass of CuSO4 dissolved in 0.03dm^3  (30cm^3) of the solution

n = m/Mr

m = n*Mr

if 0.1 mol is dissolved in 0.5 dm^3 of water

0.5/0.03 ≈ 16.66666667

0.1 = 0.05

0.1 / 16.66666667 = 0.006

0.5 / 16.66666667 = 0.03

0.006 (mol of CuSO4) = 0.03 (dm^3 solution)

0.006 * 159.5 = 0.957 g

I think this is the answer