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Gennadij [26K]
1 year ago
8

The mass of an object is 500.25g and its volume is 10.05cm³. What is its density?

Chemistry
1 answer:
harkovskaia [24]1 year ago
5 0
Hello the density is 49.78 g/cm^3 of the object
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Which metal is used to make gasmasks ​
Lubov Fominskaja [6]

Explanation:

Gas mask filters include activated carbon,

absorbents that trap toxins in millions of micro-pores. It is the same compound used to filter water and treat ingestion of poisons. The activated carbon traps the toxins, but in gas masks it is further augmented with metal oxides, such as copper and molybdenum, to help break down the toxins.

A lot of research is being done in Berkeley labs

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3 years ago
A chemist wishes to perform the following reaction: N2 + 3 H2 → 2 NH3 If only 14.0 g of N2 is available, what is the minimum amo
djyliett [7]

Answer:

3 grams

Explanation:

14 g of N2   is 1/2 mole

  If you halve the N2   in the balanced equation , you have to halve the H2 down to 1.5 moles of H2    which is 3 grams

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2 years ago
The diagram below shows earth as viewed from space as it moves around the sun approximately how long does it take earth to move
andriy [413]

Answer:

It would take 12 hours.

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5 0
3 years ago
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Which of the following help a chemical reaction to happen faster? Molecule ,Atom, Density , Catalyst
Gemiola [76]

Answer:

I am pretty sure that is a : Catalyst but if i'm not correct sorry

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2 years ago
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A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
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