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STALIN [3.7K]
2 years ago
11

A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is

Engineering
1 answer:
Sauron [17]2 years ago
4 0

The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

  • a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>
  • b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the  isotropic antenna, G = 15 times

The gain in dBi is given as follows;

\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}

Which gives;

\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }

\displaystyle \dfrac{G(dBi)}{10}  = \frac{ln(15)}{ln(10)}

\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

\displaystyle G  = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

  • \displaystyle The \ power \ received \ by \ the \ isotropic \ antenna  = \frac{1 \, mW}{1.64}  \approx \underline {0.61 \, mW}

Learn more here:

brainly.com/question/17587029

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olga2289 [7]

Answer:

1) The probability of at least 1 defective is approximately 45.621%

2) The probability that there will be exactly 3 shipments each containing at least 1 defective device among the 20 devices that are tested from the shipment is approximately 16.0212%

Explanation:

The given parameters are;

The defective rate of the device = 3%

Therefore, the probability that a selected device will be defective, p = 3/100

The probability of at least one defective item in 20 items inspected is given by binomial theorem as follows;

The probability that a device is mot defective, q = 1 - p = 1 - 3/100 = 97/100 = 0.97

The probability of 0 defective in 20 = ₂₀C₀(0.03)⁰·(0.97)²⁰ ≈ 0.543794342927

The probability of at least 1 = 1 - The probability of 0 defective in 20

∴ The probability of at least 1 = 1 - 0.543794342927 = 0.45621

The probability of at least 1 defective ≈ 0.45621 = 45.621%

2) The probability of at least 1 defective in a shipment, p ≈ 0.45621

Therefore, the probability of not exactly 1 defective = q = 1 - p

∴ q ≈ 1 - 0.45621 = 0.54379

The probability of exactly 3 shipment with at least 1 defective, P(Exactly 3 with at least 1) is given as follows;

P(Exactly 3 with at least 1) = ₁₀C₃(0.45621)³(0.54379)⁷ ≈ 0.160212

Therefore, the probability that there will be exactly 3 shipments each containing at least 1 defective device among the 20 devices that are tested from the shipment is 16.0212%

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I = 48 mA, R = 1125 2. What is Vs ?
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A composite wall is to be used to insulate a freezer chamber at -350C. Two insulating materials are to be used with conductiviti
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Answer:

thickness1=1.4m

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Explanation:

you must use this equation to calculate the thickness:

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L1=0.04*(0--350)/10=1.4m

L2=0.1(220-0)/10=2.2m

Then use this equation to calculate the convective coefficient

H=Q/(T2-T1)

H=10/(250-220)=0.33W/m^2K

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