The 500 lb load is being hoisted at a constant speed using the motor M, which has a weight of 50 lb. The beam has a weight of 40
lb/ft and is fixed to the wall at A. Find axial, shear force and bending moment at point B. (Radius of the pulley wheel is 1 ft)
1 answer:
Answer:
The answer and explanation is attached.
Explanation:
The 500 lb load is being hoisted at a constant speed using the motor M, which has a weight of 50 lb. The beam has a weight of 40 lb/ft and is fixed to the wall at A. Find axial, shear force and bending moment at point B. (Radius of the pulley wheel is 1 ft)
The answer and explanation is attached.
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Answer:
P=361.91 KN
Explanation:
given data:
brackets and head of the screw are made of material with T_fail=120 Mpa
safety factor is F.S=2.5
maximum value of force P=??
<em>solution:</em>
to find the shear stress
T_allow=T_fail/F.S
=120 Mpa/2.5
=48 Mpa
we know that,
V=P
<u>Area for shear head:</u>
A(head)=π×d×t
=π×0.04×0.075
=0.003×πm^2
<u>Area for plate:</u>
A(plate)=π×d×t
=π×0.08×0.03
=0.0024×πm^2
now we have to find shear stress for both head and plate
<u>For head:</u>
T_allow=V/A(head)
48 Mpa=P/0.003×π ..(V=P)
P =48 Mpa×0.003×π
=452.16 KN
<u>For plate:</u>
T_allow=V/A(plate)
48 Mpa=P/0.0024×π ..(V=P)
P =48 Mpa×0.0024×π
=361.91 KN
the boundary load is obtained as the minimum value of force P for all three cases. so the solution is
P=361.91 KN
note:
find the attached pic
Answer:
Explanation:
The adiabatic throttling process is modelled after the First Law of Thermodynamics:
Properties of water at inlet and outlet are obtained from steam tables:
State 1 - Inlet (Liquid-Vapor Mixture)
State 2 - Outlet (Superheated Vapor)
The change of entropy of the steam is derived of the Second Law of Thermodynamics:
Answer:
a)5.28 Å , b)3.73 Å , c)3.048 Å
Explanation:
the atoms are situated only at the corners of cube.Each and every atom in simple cubic primitive at the corner is shared with 8 adjacent unit cells.
Therefore, a particular unit cell consist only 1/8th part of an atom.
The lattice constant of a simple cubic primitive cell is 5.28 Å
We know formula of distance,
d =
a)(100)
a=5.28 Å
Distance = =5.28 Å
b)(110)
Distance = = 3.73 Å
c)(111)
Distance= = 3.048 Å