The 500 lb load is being hoisted at a constant speed using the motor M, which has a weight of 50 lb. The beam has a weight of 40
lb/ft and is fixed to the wall at A. Find axial, shear force and bending moment at point B. (Radius of the pulley wheel is 1 ft)
1 answer:
Answer:
The answer and explanation is attached.
Explanation:
The 500 lb load is being hoisted at a constant speed using the motor M, which has a weight of 50 lb. The beam has a weight of 40 lb/ft and is fixed to the wall at A. Find axial, shear force and bending moment at point B. (Radius of the pulley wheel is 1 ft)
The answer and explanation is attached.
You might be interested in
Answer:
Hello the needed data given is not properly arranged attached below is the properly arranged data
Answer:
b) 62.5 * 10^3 MPa
c) ≈ 285 MPa
d) 370Mpa
e) 16%
Explanation:
Given Data:
cylindrical aluminum diameter = 12.8 mm
Gauge length = 50.8 mm
A) plot of engineering stress vs engineering strain
attached below
B ) calculate Modulus of elasticity
Modulus of elasticity = Δб / Δ ε
= ( 200 - 0 ) / (0.0032 - 0 ) = 62.5 * 10^3 MPa
C) Determine the yield strength
at strain offset = 0.002
hence yield strength ≈ 285 MPa
D) Determine tensile strength of the alloy
The tensile strength can be approximated at 370Mpa because that is where it corresponds to the maximum stress on the stress vs strain ( complete plot )
E) Determine approximate ductility in percent elongation
ductility in percent elongation = plastic strain at fracture * 100
total strain = 0.165 , plastic strain = 0.16
therefore Ductility in percent elongation = 0.16 * 100 = 16%
