Answer:
3.8 secs
Explanation:
Parameters given:
Acceleration due to gravity, g = 9.8
Initial velocity, u = 11.76 m/s
Final velocity, v = 49 m/s
Using one of Newton's equations of linear motion, we have that:
where t = time of flight of arrow
The sign is positive because the arrow is moving downward, in the same direction as gravitational force.
Therefore:
The arrow was in flight for 3.8 secs
Answer:
D) ¼ as large
Explanation:
The magnitude of the electric force between two charges is
where
k is the Coulomb's constant
q1 and q2 are the magnitudes of the two charges
r is the separation between them
From the formula we see that the magnitude of the force is inversely proportional to the square of the distance.
In this problem, the distance is doubled:
So the new force will be
So the force will decrease to 1/4 of its original value.