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3 years ago

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The strong crystal structure of an ionic compound is one of the main reasons why ionic compounds have a __________ melting point

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1 answer:

Alisiya [41]3 years ago

6 0

Answer:

high

Explanation:

The strong crystal structure of an ionic compound is one of the main reasons why ionic compounds have a high melting point.

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The outer electrons in an element are referred to as _____. valence electrons ground state electrons excited electrons none of t

scZoUnD [109]

This should be valence electrons. They determine the chemical properties of an atom.

4 0

3 years ago

Read 2 more answers

What type of reaction results in the formation of a salt?

kolezko [41]

Salt, in chemistry, substance produced by the reaction of an acid with a base. A salt consists of the positive ion (cation) of a base and the negative ion (anion) of an acid. The reaction between an acid and a base is called a neutralization reaction. Hope this helps!!!

5 0

3 years ago

With full explaniation

zzz [600]

A. The ball's (vertical) velocity $v$ at time $t$ is

$v(t) = 30\dfrac{\rm m}{\rm s} - gt$

so that after 4 seconds, the ball's speed is

$|v(4\,\mathrm s)| = \left|30\dfrac{\rm m}{\rm s} - \left(10\dfrac{\rm m}{\mathrm s^2}\right) (4\,\mathrm s)\right| = \boxed{10\frac{\rm m}{\rm s}}$

(The velocity is -10 m/s, so the ball is falling back down at this point.)

B. At maximum height, the ball has zero velocity, so it takes

$30\dfrac{\rm m}{\rm s} - gt = 0 \implies t = \dfrac{30\frac{\rm m}{\rm s}}g = \boxed{3\,\mathrm s}$

for the ball to reach this height.

C. The height of the ball $y$ at time $t$ is

$y(t) = \left(30\dfrac{\rm m}{\rm s}\right) t - \dfrac g2 t^2$

The maximum height is attained by the ball at 3 seconds after it's thrown, so

$y_{\rm max} = \left(30\dfrac{\rm m}{\rm s}\right) (3\,\mathrm s) - \dfrac{10\frac{\rm m}{\mathrm s^2}}2 (3\,\mathrm s)^2 = \boxed{45\,\mathrm m}$

D. The time it takes for the ball to reach its maximum height is half the time it spends in the air. So the total airtime is $\boxed{6\,\mathrm s}$ .

Put another way: When the ball returns to the height from which it was thrown, its final velocity has the same magnitude as its initial velocity but points in the opposite direction. This is to say, after the total time the ball is in the air, it's final velocity will be -30 m/s. Then the total airtime is

$30\dfrac{\rm m}{\rm s} - gt = -30\dfrac{\rm m}{\rm s} \implies t = \dfrac{60\frac{\rm m}{\rm s}}g = \boxed{6\,\mathrm s}$

Put yet another way: Solve $y(t) = 0$ for $t$ . I don't see a need to elaborate...

5 0

2 years ago

A football is kicked with an initial speed of 11.0 m/s, at an angle of 35degrees above the horizontal across horizontal ground.

nalin [4]

Answer:

<em>The range of the ball is 11.6 meters</em>

Explanation:

<u>Projectile Motion </u>

It's the type of motion that experiences an object launched with an initial angle and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

$\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}$

The football is kicked with an initial speed of vo=11 m/s at an angle of θ=35°.

Calculating the range:

$\displaystyle d={\frac {11^{2}\sin(2\cdot 35^\circ)}{9.8}}$

$\displaystyle d={\frac {121\sin(70^\circ)}{9.8}}$

d = 11.6 m

The range of the ball is 11.6 meters

8 0

3 years ago

A 0.15 kg mass is suspended from a vertical spring and descends a distance of 4.6 cm, after which it hangs at rest. An additiona

ch4aika [34]

Answer:

The total extension = 19.9 cm

Work done in stretching the spring through both displacement = <em>0.633 J.</em>

Explanation:

From Hook's law,

F = ke .................................... Equation 1.

Where F = force or weight, k = force constant of the spring, e = extension.

making k the subject of the equation,

k = F/e .......................... Equation 2

Given: F = W = mg = 0.15(9.8) = 1.47 N, e = 4.6 cm = 0.046 m.

k = 1.47/0.046

k = 31.96 N/m.

When an additional mass of 0.5 kg is suspended,

Total mass suspended(M₁) = 0.15+0.5 = 0.65 kg

Total Weight (W₁) = 0.65(9.8) = 6.37 N.

k = 31.96 N/m

Substituting into equation 1

6.37 = 31.96e

e = 6.37/31.96

e = 0.199 m

e = 19.9 cm

Thus the total extension = 19.9 cm

a.

Work done in stretching the spring through both displacement

W = 1/2ke²..................... Equation 3

Where W = work done, k = spring constant, e = extension.

Given: k = 31.96 N/m, e = 0.199 m

Substituting into equation 3

W = 1/2(31.96)(0.199)²

<em>W = 0.633 J.</em>

5 0

3 years ago